1Comprehensive Exam Review12/03/2009Structure & Properties of WaterBent geometry, O-H bond length of 0.958Å Can form Hydrogen bondsHenderson - Hasselbalch equation]][[HAAHK−+=From][−+=AHAKHRearrangeTake (-)Log of each][loglogHAAKpH−+−=][logHAApKpH−+=The 6step approach1. Write the Henderson + Hasselbalch equation.2. Write the acid base equation 3. Make sure either an H+or OH-is in the equation.3. Find out what you are solving for4. Write down all given values.5. Set up equilibrium conditions.6. Plug in H + H equation and solve.What is the pH of a solution of that contains 0.1M CH3COO-and 0.9 M CH3COOH?1) pH = pK + Log [A-][HA]2) CH3COOHCH3COO-+ H+3) Find pH4) pK = 4.76 A-= 0.1 M HA = 0.9 M5) Already at equilibrium6)X = 4.76 + Log 0.10.9Log 0.111 = -.95 X = 4.76 + (-.95) X = 3.81Amino AcidsYou must know Table 4.1 p76-77:Their namesTheir structureTheir three letter codeh ildTheir one letter codeTyrosine, Tyr, Y, aromatic, hydroxyl
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