IRWIN 9e 13_36

# IRWIN 9e 13_36 - Inivin Basic Engineering Circuit Analysis...

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Unformatted text preview: Inivin, Basic Engineering Circuit Analysis. 9/E 1 1336 Fiml the inverse Lu]1iz:cclrur1.~:ikirrn of the i'niiaiwing ['1I nut inns. _ _ I?" {a} Hill - 5 1 _ _ 1 _ 9-2.: {h} Hill - F r} r - 1‘ F c [:5] _ 5 + 2 SOLUTION: -S (00 Pm = e 5-H GM): ' S‘H get) : e—tbLC‘t) Hg): e'S 67(5) and. Flt):9(£") MW) FCt) : C'C’C”) LACE-U (5) Fa) : we“ 5 Us): .L _ 5:: 5 3 67(5) : I ._———- 5 got) : Lift) Chapter 13: The Laplace Transform Problem 13.36 2 Irwin, Basic Engineering Circuit Analysis. 9/E N31 2 _l_ —— e G; (5) 5 PM): LL({')” apt-2) (C) m; : Ire" 5+1 PCS) : I _ 6* 5+2 5+2 91(5) I _l___ 5+2 9m : cit FCf): e‘ch («MH'C’ZUC-U um; ~/) __________________.__.__._._——-————- , Problem 13.36 Chapter 13: The Laplace Transform ...
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