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IRWIN 9e 13_40

# IRWIN 9e 13_40 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis, 9/E 1 134:} Salve the j'ouJnu-‘ing differential equatinnr; ming- Laplace tranatm'ma. :11:th dr cit“) J: + 4x“: = (2", 1m} = 1 [a] {b} + mgr) = man), mm = 2 SOLUTION: @1) CLXLt) # L{X(f)': aflt oUc X(o):l SXCU" Mb)T’VXU)=:_i_W 3+2 8+1 §+L+J X65} ~ _ﬂ§iﬂevﬂﬂﬁ 3‘“! X“): S+3 (Baum) KB): A + 8 3+2 5+V L: A + 8 (5+2) (ﬁg) S 7‘"). 5 -f L4 Chapter 13: The Laplace Transform Problem 13.40 2 Irwin. Basic Engineering Circuit Analysis, 9/E NS) 3 J41” —’r V; --t Mic): ’éECQ’ +1416”? ace) (b) _QL'Y;(’C) +6100 3 Wu (H X(Q):’L (M r 37((5)‘ 1(0) + 6x0) :— L4 .ﬁ. 5 (346) Ms) 1 3+2. 5 N5) = My SC\$+e) 13+»! Iii—f 13 59%) 3 He Problem 13.40 Chapter 13: The Laplace Transform Irwin. Basic Engineering Circuit Analysis, 9/E 3 2\$+L4 1 Mus) +865) Lei 5:0 L4: Me) Chapter 13: The Laplace Transform Problem 13.40 ...
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• Spring '06
• cihan
• Microphone, Basic Engineering Circuit, Engineering Circuit Analysis, Laplace transform problem, Laplace Transform Irwin

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