IRWIN 9e 13_56

# IRWIN 9e 13_56 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis. 9/E 1 _________________________._.____———-— 13.56 The switch in 111:: circuit in Fig. Pl 3.56 has; hem (flux-it‘d [11m Jung time and is. Upcncd at I = D. Fiml {III} 1hr I E] 115ng Laplace tranat‘mnm. Figure P1356 SOLUTION: Problem 13.56 Chapter 13: The Laplace Transform 2 Irwin, Basic Engineering Circuit Analysis, 9/E vcm') : I’L-Hl: ZHV prim: + warx)+zamew1Lm+ 2 act): 12 out 31%;), T IO ILCS) + 25 ILCS)- 212(5):? Lm [Ant m 2;] :1; + 1(3) S ILLS) [Zéfiiosﬂ] - ‘63‘ +/z 3 S IL(S) : #65 +IL QSZ'HOS'H ILLS) : ~3s+g 51+5§+06 11(5): ‘~33+e (gm-I) (swag L Problem 13.56 Chapter 13: The Laplace Transform Irwin, Basic Engineering Circuit Analysis. 9/E 3 IL(S): A “f 8 3+0» 5+Lr'ci *3346' : A + g (groom—ma) Ho-i 34L” -3s+6: A(s+q.q)+g(s+m) Lax: _L,,q ~3(~H'4)+6: g(-g.q+o.,) 8: we} Lei: S: *O'l —3( ~04) +6 : APO/HM) A : I'3i 1L8) 2 "3' + ~q'3i \$+O| s+L/.q —— r — ' it 4(1): (we 0’3 were ‘4 q ) (AHA ________________.___——————————— Chapter 13: The Laplace Transform Problem 13.56 ...
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## This note was uploaded on 02/22/2011 for the course EEE 202 taught by Professor Cihan during the Spring '06 term at ASU.

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