IRWIN 9e 7_14

# IRWIN 9e 7_14 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis, 9/E 1 In“. List: the Llit'i'erciitiail cquatimt tippi'amuii m i'iml iii} i'nr I D in tho circuit in Fig. P?.l-—i- and tho pint 1hr: 11351101th including the time interval just ]‘Ii'iﬂf In ripening the switch. 5 H51 1_ I = 0 2 ilﬂ 1 I'll} HH—H N—I—W-w—J §2kﬂ \$1M} Figure Pixie. SOLUTION: £03 i=0— Ri= 5m Ranks; ikﬂ‘ iﬁo'): SmA, all, U%'UAL W will vow «Kuwait; 13kg SiaO/bi' Mcw' R‘= KK5+R¢> ii R4} re; 12’: Sup; R'= 5M2. ___—__—___———-————————_—"——— ; Chapter 7: First— and Second- Order Transient Circuits Problem 7.14 2 InNin, Basic Engineering Circuit Analysis. 9/E KCL‘. 1,, (J: nwaﬁm m) v (t) .. ali— l . (3+ “57>L Ola—SQ + AM) «0 51100 R i’ ,L :t _ 011’ +(922Hz’) '0 RLR’ :0 7+€R1+KQL K R‘ —. W al.- Am»- Ac LR1+P~’)L 110% swam A : 5M53 . 5 L(t)’5€‘7.SXIDxWA ) 170 Problem 7.14 Chapter 7: First- and Second- Order Transient Circuits Irwin, Basic Engineering Circuit Analysis, 9/E 3 ___________.___________.__—————- Chapter 7: First- and Second— Order Transient Circuits Problem 7.14 s ...
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