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IRWIN 9e 7_56

# IRWIN 9e 7_56 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis. 91E 1.515 Fiml the output wailiugc iL'DIIIII in the netwm'k in Fig. PTﬁﬁ it'le input wattage i5 “HI-[ﬂ = ﬁiuﬂr} — iii: — ﬂﬂﬁjj'v'. 1 p.F + 13,-“) 100 m uni!) Figure P746 SOLUTION: 1 “F + vim 100 kﬂ 220(1) View 5[w(t)—Lc<t—o-os)]v V: (v) 5 I —‘—To__——‘9 ‘ X5003) OSt g 50 ms #Voét): k'T/(l C‘t/T f > 50m\$ V0 (f) : kg '7' kg C'tm‘ Chapter 7: First- and Second- Order Transient Circuits Problem 7.56 2 I Irwin, Basic Engineering Circuit Analysis, 9/E \<\+ kl: 5 at:OO V0 ‘-= \0V K]: O k; : lRQQ, looks» [email protected]% 5 T: ch "I": (100k)(iu.) 7": 0-13 VOCE): k1+ K; C’t'T Problem 7.56 Chapter 7: First- and Second- Order Transient Circuits Irwin, Basic Engineering Circuit Analysis, 9/E 3 \/ 56 —Io(5’ox10'3) 0 = V0: MW 3% 12-.- 50 ms+ Va: l-‘WV V0: VLn’VC. Vo = 4-9? ks'i' 5 3M V0; 0 kw : 0 /C3: “L77 VD (t): T kw C'tIT \lott): -;.q~/ e-Ioﬂ-o-os‘) V) f >50m VDUI): Sad“: V OSJC 5 50mg ‘ ‘ \/ '6 >5Dms ___—___—__—_—_.—_——————————————-— Chapte‘r 7: First— and Second- Order Transient Circuits Problem 7.56 L ...
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