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IRWIN 9e 7_78

IRWIN 9e 7_78 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin. Basic Engineering Circuit Analysis, 97E _ 1 1.?3 Find ugh) for I 2} II} in the circuit in Fig. P'II‘JB if mm) = fl. Figure Pirqrfl SOLUTION: _ 't = O ‘ 1 k0 2!. (0-) AL (0' : 0A ikn. 'OOMH l2\l * Cit 451(6) k dz; (6) .LI (6 :0 R2Lét)+ Litifaéfl 4. é]£._(e)olt =l2. ‘ Chapter 7: First— and Second- Order Transient Circuits Problem 7.78 2 I Irwin. Basic Engineering Circuit Analysis. 9/E alt“- L at LC )3 13' .2. - 1— L 4.1- LC. 0 loam (loom)(l,u) ¢L+IOXIOB¢+ name: 0 ’8: —/0X’03 2t 'x/C/OX/oa): 403(onioé) 2.0) 4: ’5000 :r 3573‘ 42: ’88'7’3 401,09): he'nfi‘t-r— k e —£873't » 3- A°L(O): DA kf+l<g_= I2: 6 «((0’" old. N L ar/e..0+ + W”) 22: Rfkfiké) -//27/<,L- 3273mm (1XI03)[K,TK,_].- 0.1.749- g8¥.3K1:/2_ 887.319 +no_.7 klziz h: ’Ka. Problem 7.78 Chapter 7: First- and Second- Order Transient Circuits Irwin, Basic Engineering Circuit Analysis, 91E 3 K‘- i5~5m Vcbt); 2.5 M (ac) dzir+ 143 \/c (0“); av o— —— i<i W , K1. K3 k3;i2. Vat); A'Cj'z‘“ Mott + k3 2L (‘6); "5‘5 6-,nj-t _._. \S.S C -88731WA V (It : i — -3 —ii27't' C ) ixro’é (IS‘SX'O e —iS'-5Ki~o‘3t'8z’73t>0(f+li , , 45 \Idt): ib~ sxio (6-11215 _1§.$“>(io'5 (23931: I \lcit): 43.75 e."'ml+l-vs‘é’gfiat-sz Chapter 7: First— and Second- Order Transient Circuits Problem 7.78 ‘ ...
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