Test1ReviewNotes - R1-1Physics IReview 1Review NotesExam...

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Unformatted text preview: R1-1Physics IReview 1Review NotesExam 1Rev. 26-Sep-04 GBR1-2DefinitionsScalar:A number – positive, negative, or 0.Magnitude:Absolute value – positive or 0.Vector:Magnitude (or length) and direction in space.Time:t (scalar)Position:x(vector)Displacement:xxx-=∆Time interval:ttt-=∆R1-3Definitions (Continued)Average or mean velocity is defined as follows:txttxxvavg∆∆≡--≡Instantaneous velocity or just “velocity”:tdxdtxlimvt≡∆∆≡→∆R1-4Definitions (Continued)Average acceleration is defined as follows:tvttvvaavg∆∆≡--≡Instantaneous acceleration or just “acceleration”:22ttdxdtdvdtvlima≡≡∆∆≡→∆R1-5Class #1Take-Away Concepts1D Equations of Motion for Constant AccelerationBasic Equations1. (29ttavv-+=2. 221)tt(a)tt(vxx-+-+=Derived Equations3. )tt)(vv(xx21-++=4. 221)tt(a)tt(vxx---+=(compare with 2.)5. (2922xxa2vv-+=R1-6Problem Solving Strategy forProjectile MotionMake a table, see what you know and what you need to find.XYavxor yvfxfor yft-tSAMESAMEThe common factor in both the X and Y equations is thetime at which something happens (last row).R1-7Hit the Falling Target DiagramdhθThe target will drop at the instantthe ball leaves the launcher.The objective is to adjust the angle θso that the ballhits the falling target.R1-8Hit the Falling TargetTable of Kinematic QuantitiesX ballY ballY targeta-g-gvvcos(θ)vsin(θ)xor yhvfvcos(θ)??xfor yfd?Same as ball.t-t?SAMESAMEWe have all data in the “X ball” column except time.Solve for that first.R1-9Hit the Falling TargetSolving for Time)cos(vd)tt()tt()cos(vxxfθ=-→-θ+=We don’t care what vfis for the ball or target (Y).X ballY ballY targeta-g-gvvcos(θ)vsin(θ)xor yhvfvcos(θ)(don’t care)(don’t care)xfor yfd?Same as ball.t-td/[vcos(θ)]SAMESAMENext, use the kinematics equation to find yf.R1-10Hit the Falling TargetSolving for Final Y PositionY ball:2f)cos(vdg21)cos(vd)sin(vyθ-θθ+=Y target:2f)cos(vdg21hyθ-+=Setting the two expressions equal, the “g” terms cancel and we are left withh)cos(d)sin(=θθORdh)tan(=θR1-11Class #2Take-Away Concepts1.X and Y motions are independent.2.In projectile motion problems, the acceleration isconstant = 9.8 m/s2down (normally -Y direction).3.Strategy for solving projectile motion problems:Create a table, fill in known quantities, work on findingunknown quantities....
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This note was uploaded on 02/23/2011 for the course ERTH 4180 taught by Professor Desimone during the Spring '11 term at Rensselaer Polytechnic Institute.

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Test1ReviewNotes - R1-1Physics IReview 1Review NotesExam...

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