Unformatted text preview: (d) Note that, since the intersection is contained in both A and B , we must have that P ( A ∩ B ) ≤ P ( A ) = . 8 and P ( A ∩ B ) ≤ P ( B ) = . 7. Therefore, P ( A ∩ B ) can be at most .7. 94. (a) P ( A ∪ B ) = P ( A ) + P ( B )P ( A ∩ B ) = . 95 + . 90. 88 = . 97 (b) P ( A ∪ B ) = 1P ( A ∪ B ) = 1. 97 = . 03 96. (a) P ( A ∪ B ) = P ( A ) + P ( B )P ( A ∩ B ) = P ( A ) + P ( B )P ( A ) P ( B ) = . 5 + . 2. 5 × . 2 = . 6 (b) P ( A ∩ B ) = P ( A ) P ( B ) = (1P ( A ))(1P ( B )) = (1. 5)(1. 2) = . 4 (c) P ( A ∪ B ) = P ( A ) + P ( B )P ( A ∩ B ) = (1. 5) + (1. 2). 4 = . 9 1...
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