DC_Analysis_of_BJT_Circuits - Analyze the circuit to...

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DC Analysis of Transistor Circuits Example 1. Analyze the circuit to determine all node voltages and branch currents given that V BE = 0.7V and = 100. 4V 10V R E = 3.3k R C = 4.7k We observe that V B = 4V. Since V BE = V B – V E , then V E = 4 – 0.7 = 3.3V. And E E E R V I 0 = 1mA. mA I I I E E C 99 . 0 1 V R I V V C C CC C 3 . 5 47 99 . 10 Since V B = 4V and V C = 5.3V, then V CB = V C - V B = 1.3V And mA I B 01 . 0 101 1
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Example 2. Analyze the circuit to determine all node voltages and branch currents given that V BE = 0.7V and is very large. 6V 10V R E = 3.3k R C = 4.7k We observe that V B = 6V. Since V BE = V B – V E , then V E = 6 – 0.7 = 5.3V And = E E E R V I 0 = 1.6mA I C I E so V I R I V V C C C CC C 48 . 2 47 10 Since V B = 6V and V C = 2.48V, then V CB = V C - V B = 2.48 6 = -3.52V Transistor operating in the saturation mode. Example 3. Analyze the circuit to determine all node voltages and branch currents given that V BE = 0.7V and = 100. 10V R E = 3.3k R C = 4.7k
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We observe that V B = 0V implying that the EBJ cannot conduct and I E = 0. The CBJ cannot conduct since the n-type collector is connected through R C to 10V while the p-type base is at ground. Therefore I C = 0. Transistor is in the Cut-off mode. Example 4.
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Unformatted text preview: Analyze the circuit to determine I C , V E , V B and R 1 given that V BE = 0.7V and is very large. V C = 12V R E = 1.2k R C = 4.7k R 2 = 5.6k R 1 V CC = 18V V E k R R V V V V V R R R V V R I R I R I V V V R I V mA R V V I E BE B CC B E C E C E E E E CE C C CC C C CC C 4 . 39 6 . 5 6 . 5 18 24 . 2 24 . 2 54 . 1 7 . 54 . 1 2 . 1 28 . 1 28 . 1 7 . 4 12 18 1 1 2 1 2 Example 5. Calculate bias voltages and currents given = 80. V i R E = 2k R B = 250k C 1 V EE = 20V I E V o C 2 V E V B I B Writing the loop equation: V R I V V I mA I I A R R V V I I I R I V R I V E E EE E E B C E B EB EE B B E B B EB E E EE 2 . 12 9 . 3 8 . 48 1 1 Example 6. Calculate bias voltages and currents given is very large. I E R E = 2k R C = 6k R 1 = 40k V EE = 10V V O R 2 = 10k C E I C V i C 2 C 1 V V V V V R I V I mA R V V I V V V V V V R R R V E C CE C C C C E E EE E EB B E EE B 8 . 4 7 . 8 9 . 3 9 . 3 6 65 . 65 . 2 7 . 8 10 7 . 8 7 . 8 8 10 10 40 40 2 1 1...
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This note was uploaded on 02/23/2011 for the course ELETRONICS P24L taught by Professor Learymyers during the Spring '11 term at University of the West Indies at Mona.

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DC_Analysis_of_BJT_Circuits - Analyze the circuit to...

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