Limiting Reactants

Limiting Reactants - . *EXAMPLE: When 8.0g CH 4 and 24g O 2...

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MOLE-TO-COEFFICIENT RATIO METHOD FOR DETERMINING THE LIMITING REACTANT (1) Calculate the no. of moles of each reactant available. (2) Divide the no. of moles of each reactant by the coefficient of that reactant in the balanced equation. (3) The reactant with the smallest mole/coefficient ratio is the limiting reactant
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Unformatted text preview: . *EXAMPLE: When 8.0g CH 4 and 24g O 2 are mixed for reaction to give CO 2 and H 2 O, which reactant is the limiting reactant? CH 4 + 2O 2 CO 2 + 2H 2 CH 4 : 8.0/16 = 0.5 moles 0.5/1 = 0.5 O 2 : 24/32 = 0.75 moles 0.75/2 = 0.375 O 2 is the limiting reactant...
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This note was uploaded on 02/23/2011 for the course CHEM 101 taught by Professor Williamson during the Spring '08 term at Texas A&M.

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