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Unformatted text preview: lai (yl8859) HW06 Ross (15200) 1 This printout should have 11 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 3) 10.0 points A boat moves through the water with two forces acting on it. One is a 2140 N forward push by the motor on the propeller, and the other is an 1879 N resistive force due to the water around the bow. What is the acceleration of the 1111 kg boat? Correct answer: 0 . 234923 m / s 2 . Explanation: Given : F 1 = 2140 N , F 2 = 1879 N , and m = 1111 kg . 2140 N 1879 N The forces are unbalanced, so the net force is F net = m a = F 1 F 2 and a = F 1 F 2 m = 2140 N 1879 N 1111 kg = . 234923 m / s 2 forward. 002 (part 2 of 3) 10.0 points If it starts from rest, how far will it move in 18 s? Correct answer: 38 . 0576 m. Explanation: Given : t = 18 s Under acceleration, x = v i t + 1 2 a ( t ) 2 = 1 2 a ( t ) 2 since v i = 0 m/s. Thus x = 1 2 a ( t ) 2 = 1 2 ( . 234923 m / s 2 ) (18 s) 2 = 38 . 0576 m . 003 (part 3 of 3) 10.0 points What will its velocity be at the end of this time interval?...
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This note was uploaded on 02/24/2011 for the course PHYS 152 taught by Professor Button during the Winter '08 term at IUPUI.
 Winter '08
 BUTTON
 mechanics, Force

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