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Unformatted text preview: lai (yl8859) – HW07 – Ross – (15200) 1 This printout should have 8 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points Consider the 650 N weight held by two cables shown below. The lefthand cable had tension T 2 and makes an angle of θ 2 with the ceiling. The righthand cable had tension 420 N and makes an angle of 49 ◦ with the ceiling. The righthand cable makes an angle of 49 ◦ with the ceiling and has a tension of 420 N . 650 N T 2 4 2 N 4 9 ◦ θ 2 a) What is the tension T 2 in the lefthand cable slanted at an angle of θ 2 with respect to the wall? Correct answer: 432 . 237 N. Explanation: Observe the freebody diagram below. F 2 F 1 θ 1 θ 2 W g Note: The sum of the x and ycomponents of F 1 , F 2 , and W g are equal to zero. Given : W g = 650 N , F 1 = 420 N , θ 1 = 49 ◦ , and θ 2 = 90 ◦ θ . Basic Concept: Vertically and Horizontally, we have F x net = F x 1 F x 2 = 0 = F 1 cos θ 1 F 2 cos θ 2 = 0 (1) F y net = F y 1 + F y 2 W g = 0 = F 1 sin θ 1 + F 2 sin θ 2 W g = 0 (2) Solution: Using Eqs. 1 and 2, we have F x 2 = F 1 cos θ 1 (1) = (420 N) cos49 ◦ = 275 . 545 N , and F y 2 = F 3 F 1 sin θ 1 (2) = 650 N (420 N) sin49 ◦ = 650 N 316 . 978 N...
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This note was uploaded on 02/24/2011 for the course PHYS 152 taught by Professor Button during the Winter '08 term at IUPUI.
 Winter '08
 BUTTON
 mechanics

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