solution-hw7 - lai(yl8859 HW07 Ross(15200 This print-out...

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lai (yl8859) – HW07 – Ross – (15200) 1 This print-out should have 8 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points Consider the 650 N weight held by two cables shown below. The left-hand cable had tension T 2 and makes an angle of θ 2 with the ceiling. The right-hand cable had tension 420 N and makes an angle of 49 with the ceiling. The right-hand cable makes an angle of 49 with the ceiling and has a tension of 420 N . 650 N T 2 420 N 49 θ 2 a) What is the tension T 2 in the left-hand cable slanted at an angle of θ 2 with respect to the wall? Correct answer: 432 . 237 N. Explanation: Observe the free-body diagram below. F 2 F 1 θ 1 θ 2 W g Note: The sum of the x - and y -components of F 1 , F 2 , and W g are equal to zero. Given : W g = 650 N , F 1 = 420 N , θ 1 = 49 , and θ 2 = 90 - θ . BasicConcept: Vertically and Horizontally, we have F x net = F x 1 - F x 2 = 0 = F 1 cos θ 1 - F 2 cos θ 2 = 0 (1) F y net = F y 1 + F y 2 - W g = 0 = F 1 sin θ 1 + F 2 sin θ 2 - W g = 0 (2) Solution: Using Eqs. 1 and 2, we have F x 2 = F 1 cos θ 1 (1) = (420 N) cos 49 = 275 . 545 N , and F y 2 = F 3 - F 1 sin θ 1 (2) = 650 N - (420 N) sin 49 = 650 N - 316 . 978 N = 333 . 022 N , so F 2 = radicalBig ( F x 2 ) 2 + ( F y 2 ) 2 = radicalBig (275 .
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