solution-hw22

solution-hw22 - lai (yl8859) HW22 Ross (15200) 1 This...

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Unformatted text preview: lai (yl8859) HW22 Ross (15200) 1 This print-out should have 8 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points Calculate the pressure at an ocean depth of 1500 m. The acceleration of grav- ity is 9 . 8 m / s 2 , atmospheric pressure is 1 . 01 10 5 Pa , and the density of the sea wa- ter is 1024 kg / m 3 . Correct answer: 1 . 51538 10 7 Pa. Explanation: Let : g = 9 . 8 m / s 2 , P = 1 . 01 10 5 Pa , = 1024 kg / m 3 , and h = 1500 m . P = P + g h = 1 . 01 10 5 Pa + (1024 kg / m 3 ) (9 . 8 m / s 2 ) (1500 m) = 1 . 51538 10 7 Pa . 002 (part 2 of 2) 10.0 points Calculate the total force exerted on the out- side of a circular submarine window of diam- eter 28 . 1 cm at this depth. Correct answer: 9 . 39775 10 5 N. Explanation: Let : r = 14 . 05 cm = 0 . 1405 m . F = P A = P r 2 = (1 . 51538 10 7 Pa) (0 . 1405 m) 2 = 9 . 39775 10 5 N ....
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This note was uploaded on 02/24/2011 for the course PHYS 152 taught by Professor Button during the Winter '08 term at IUPUI.

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solution-hw22 - lai (yl8859) HW22 Ross (15200) 1 This...

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