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solution-hw22

# solution-hw22 - lai(yl8859 HW22 Ross(15200 This print-out...

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lai (yl8859) – HW22 – Ross – (15200) 1 This print-out should have 8 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points Calculate the pressure at an ocean depth of 1500 m. The acceleration of grav- ity is 9 . 8 m / s 2 , atmospheric pressure is 1 . 01 × 10 5 Pa , and the density of the sea wa- ter is 1024 kg / m 3 . Correct answer: 1 . 51538 × 10 7 Pa. Explanation: Let : g = 9 . 8 m / s 2 , P 0 = 1 . 01 × 10 5 Pa , ρ = 1024 kg / m 3 , and h = 1500 m . P = P 0 + ρ g h = 1 . 01 × 10 5 Pa + (1024 kg / m 3 ) (9 . 8 m / s 2 ) (1500 m) = 1 . 51538 × 10 7 Pa . 002 (part 2 of 2) 10.0 points Calculate the total force exerted on the out- side of a circular submarine window of diam- eter 28 . 1 cm at this depth. Correct answer: 9 . 39775 × 10 5 N. Explanation: Let : r = 14 . 05 cm = 0 . 1405 m . F = P A = P π r 2 = (1 . 51538 × 10 7 Pa) π (0 . 1405 m) 2 = 9 . 39775 × 10 5 N . 003 (part 1 of 2) 10.0 points In a car lift used in a service station, com- pressed air exerts a force on a small piston of circular cross-section having a radius of 3 . 84 cm. This pressure is transmitted by a liquid to a second piston of radius 19 cm.

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