solution-hw25

solution-hw25 - lai (yl8859) – HW25 – Ross – (15200)...

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Unformatted text preview: lai (yl8859) – HW25 – Ross – (15200) 1 This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points A sound wave has a frequency of 694 Hz in air and a wavelength of 0 . 55 m. What is the temperature of the air? As- sume the velocity of sound at 0 ◦ C is 331 m / s. Correct answer: 90 . 0371 ◦ C. Explanation: Let : f = 694 Hz , λ = 0 . 55 m , v = 331 m / s , and T = 0 ◦ C + 273 = 273 K . The relationship between the speed of sound in air and Kelvin temperature is v = v radicalbigg T 273 K = f λ T = (273 K) parenleftbigg f λ v parenrightbigg 2 − 273 = (273 K) bracketleftbigg (694 Hz) (0 . 55 m) 331 m / s bracketrightbigg 2 − 273 = 90 . 0371 ◦ C . 002 10.0 points By proper excitation, it is possible to pro- duce both longitudinal and transverse waves in a long metal rod. In a particular case, the rod is 101 cm long and 0 . 304 cm in radius and has a mass of 46 . 8 g. Find the required tension in the rod so that the ratio of the speed of longitudinal waves to the speed of transverse waves is 12. Young’s modulus for the material is 7 . 3 × 10 10 N / m 2 . Correct answer: 14718 . 3 N. Explanation: Let : ℓ = 101 cm = 1 . 01 m , r = 0 . 304 cm = 0 . 00304 m , m = 46 . 8 g = 0 . 0468 kg , Y = 7 . 3 × 10 10 N / m 2 , and n = 12 ....
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This note was uploaded on 02/24/2011 for the course PHYS 152 taught by Professor Button during the Winter '08 term at IUPUI.

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solution-hw25 - lai (yl8859) – HW25 – Ross – (15200)...

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