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Unformatted text preview: 3. Losses: There is the 40 dB loss to 1 m, then an additional 10(3 . 0) log 10 d dB. So98(dBm) = 0(dBm) + 6(dB)40(dB)30 log 10 ( d/ 1m) (2) Solving for d , we have . d = (1m)10 64 / 30 = 136m . (3) For part two of this question, now the 98 is reduced to 99 dBm. Eectively, the LHS of (2) becomes one lower. This increases the 64 on the RHS of (3) to 65, and so d = (1m)10 65 / 30 = 147m....
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 Spring '10
 Dr.NealPatwari

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