homework6a_solution

# homework6a_solution - ECE 5325/6325 Fall 2009 Homework 6(a...

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Unformatted text preview: ECE 5325/6325 Fall 2009: Homework 6(a) Solution Name BPSK DPSK QPSK 16-QAM 64-QAM 2-non-co-FSK 2-co-FSK Waveforms cos(2πfc t) cos(2πfc t) cos(2πfc t), sin(2πfc t) cos(2πfc t), sin(2πfc t) cos(2πfc t), sin(2πfc t) cos(2πfc t), cos(2π (fc + ∆f )t) cos(2πfc t), cos(2π (fc + ∆f )t) P [bit error] =Q = 1 2 Bandwidth Rs (1 + α) Rs (1 + α) Rs (1 + α) Rs (1 + α) Rs (1 + α) Rs (2 + α) Rs (2 + α) exp 2Eb N0 E − Nb 0 2Eb N0 4Eb 5N0 2Eb 7N0 − 2Eb0 N Eb N0 =Q ≈ 3Q 4 ≈ = 7 12 Q 1 2 exp =Q Table 1: Waveforms, P [bit error], and bandwidth for several modulations. 10 −1 Probability of Bit Error 10 10 10 10 10 10 −2 −3 −4 −5 −6 −7 BPSK/QPSK DPSK 16−QAM 64−QAM 2nonco FSK 2co FSK 5 10 Eb/N0 (dB) 15 20 0 Figure 1: Comparison of probability of bit error formulas. ...
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## This note was uploaded on 02/25/2011 for the course ECE 5325 taught by Professor Dr.nealpatwari during the Spring '10 term at Utah.

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