EE411_HW2_Soln

# EE411_HW2_Soln - Ans From the loop formed by 12V 2 and 4 we...

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Ans: From the loop formed by 12V, 2Ω and 4Ω, we have 0 ) ( 4 ) ( 2 12 3 1 2 1 i i i i From the loop formed by 12V, 8Ω and the VCVS, we have 0 ) ( 2 2 8 12 2 1 2 i i i At the node that the 3A flowing in, we have 3 2 3 i i Solve the above 3 equations, we can obtain i 1 =3.5A, i 2 =-0.5A and i 3 =2.5A.

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Ans: V V V k V I
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## This note was uploaded on 02/24/2011 for the course EE 411 taught by Professor Lee during the Spring '07 term at University of Texas.

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EE411_HW2_Soln - Ans From the loop formed by 12V 2 and 4 we...

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