EE411_HW8&9_Soln - 1 1 3 5 6 5 Z j Z j Z So ) 601 ....

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Prof. R. Gharpurey Due Date: Apr. 6, 2010 Ans: 0 76 . 4 12 . 14 ) 10 40 ( ) 5 20 ( ) 10 40 )( 5 20 ( j T e j j j j Z 0 0 270 90 94 . 52 10 40 40 5 20 5 60 j j ab e j j j e V
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Ans:From superposition, we have 055 . 0 0941 . 0 10 50 50 10 40 40 10 50 50 10 // 40 60 30 40 60 60 40 50 50 40 60 60 40 // 50 10 20 45 j j j j j j j j e j j j j j I j o Ans:From superposition, we have V v e j j j j j e v e j j j j v o j j o j o 10 4633 . 21 2 . 19 6 . 9 2 2 12 / 2 1 // 6 2 2 12 / 2 1 // 6 4 7331 . 10 12 / 3 1 // ) 2 3 ( 6 12 / 3 1 // ) 2 3 ( 12 3 43 . 63 90 2 57 . 26 1 So 10 ) 43 . 63 2 cos( 4633 . 21 ) 57 . 26 3 cos( 7331 . 10 o o o t t v
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Ans: ) 3 2 ( 1 ) 3 2 1 ( 20 3 1 5 3 2 3 ) 3 2 //( 1 20 3 2 1 ) 3 2 ( 1 5 3 2 3 ) 3 2 //( 1 20 ) 3 2 //( 1 5 Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z Z v o Where 80 3 , 10 4 . 0 10 2 , 10 2 . 0 10
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Unformatted text preview: 1 1 3 5 6 5 Z j Z j Z So ) 601 . 40 10 cos( 6155 . 3 6155 . 3 3529 . 2 7451 . 2 5 601 . 40 o j o t e j v Ans:(c) Ans:We short the voltage source and open the current source, then find the impedance Z in parallel with Z L , we have 154 . 10 231 . 21 20 20 80 10 80 10 20 40 // 40 80 // 10 j j j j j j Z So 154 . 10 231 . 21 * j Z Z L...
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EE411_HW8&9_Soln - 1 1 3 5 6 5 Z j Z j Z So ) 601 ....

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