stats8 - 0.1 = 1.28. 5. In this case you would reject the...

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1. Formulate the null and alternative hypotheses: The null hypothesis would be anything less than or equal to 83. The alternative hypothesis would be anything greater than 83. H : μ < 83 Hı: μ > 83 2. The desired level of significance is 10% because of the 90% confidence level. 3. The test statistic is 8.571. Which is shown by 89-83/(3.5/sqrt25)=8.571. 4. The decision rule is the null hypothesis should be rejected if the alternative hypothesis is greater than the null hypothesis shown by z>z
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Unformatted text preview: 0.1 = 1.28. 5. In this case you would reject the null hypothesis because z=8.571>z 0.1 =1.28. Based on this sample data you could say with a 90% confidence that your class is better with an average of 89 versus the standard average of 83. The test is one-sided because the alternative hypothesis only falls into one side of the tails. Which would be at the greater end because we rejected the null hypothesis....
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This note was uploaded on 02/25/2011 for the course STATISTICS WL110 taught by Professor Talton during the Winter '11 term at National American.

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