Unformatted text preview: 52 cards we need to select Fve to form a poker hand thus we have ± 52 5 ² = 2598960 , unique poker hands. Problem 15 (pairings in dancing) We must Frst choose Fve women from ten in ± 10 5 ² possible ways, and Fve men from 12 in ± 12 5 ² ways. Once these groups are chosen then we have 5! pairings of the men and women. Thus in total we will have ± 10 5 ² ± 12 5 ² 5! = 252 · 792 · 120 = 23950080 , possible pairings....
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 Winter '08
 G.JOGESHBABU
 Counting, Probability, Harshad number, Card game, different outcomes, Poker hands, ﬁrst award

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