Unformatted text preview: ³ committees and subcommittee. Now assume that we pick the subcommittee ±rst. This can be done in ² n i ³ ways. We then pick the committee in ² ni ji ³ ways resulting in a total ² n i ³² ni ji ³ . Part (b): I think that the lower index on this sum should start at i (the smallest subcommittee size). If so then we have n ± j = i ² n j ³² j i ³ = n ± j = i ² n i ³² ni ji ³ = ² n i ³ n ± j = i ² ni ji ³ = ² n i ³ ni ± j =0 ² ni j ³ = ² n i ³ 2 ni ....
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 Winter '08
 G.JOGESHBABU
 Probability, Committee, smallest subcommittee size

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