HW 6 - wolz (cmw2833) HW 6 ODELL (54615) 1 This print-out...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: wolz (cmw2833) HW 6 ODELL (54615) 1 This print-out should have 20 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points Determine A so that the curve y = 4 x + 15 can be written in parametric form as x ( t ) = t- 4 , y ( t ) = At- 1 . 1. A =- 3 2. A = 5 3. A = 4 correct 4. A =- 5 5. A =- 4 6. A = 3 Explanation: We have to eliminate t from the parametric equations for x and y . Now from the equation for x it follows that t = x + 4. Thus y = 4 x + 15 = A ( x + 4)- 1 . Consequently A = 4 . 002 10.0 points Find a Cartesian equation for the curve given in parametric form by y ( t ) = 1 2 t 2 , x ( t ) = 1 8 t 3 . 1. y = 2 x 4 / 3 2. y = 2 x 2 / 3 correct 3. y = 2 x 3 / 2 4. y = x 4 / 3 5. y = x 2 / 3 6. y = x 3 / 2 Explanation: We have to eliminate the parameter t from the equations for x and y . But from the equation for x , it follows that t = 2 x 1 / 3 , in which case y = 1 2 parenleftBig 2 x 1 / 3 parenrightBig 2 = 2 x 2 / 3 . 003 10.0 points Find a Cartesian equation for the curve given in parametric form by x ( t ) = 4 cos 2 2 t, y ( t ) = 5 sin 2 2 t. 1. x 5 + y 4 = 1 20 2. 5 x- 4 y = 20 3. x 4- y 5 = 1 20 4. 4 x + 5 y = 20 5. x 5- y 4 = 1 20 6. 5 x + 4 y = 20 correct Explanation: We have to eliminate the parameter t from the equations for x and y . Now cos 2 + sin 2 = 1 . Thus x 4 + y 5 = 1 . But then after simplification, the curve has Cartesian form 5 x + 4 y = 20 . wolz (cmw2833) HW 6 ODELL (54615) 2 004 10.0 points Determine a Cartesian equation for the curve given in parametric form by x ( t ) = 3 ln(4 t ) , y ( t ) = t. 1. y = 1 2 e 6 /x 2. y = 1 2 e x/ 6 correct 3. y = 1 3 e 4 /x 4. y = 1 3 e x/ 2 5. y = 1 2 e x/ 3 6. y = 1 3 e x/ 4 Explanation: We have to eliminate the parameter t from the equations for x and y . Now from the equation for x it follows that t = 1 4 e x/ 3 . But then y = parenleftBig 1 4 e x/ 3 parenrightBig 1 / 2 = 1 2 e x/ 6 . 005 10.0 points Describe the motion of a particle with posi- tion P ( x, y ) when x = 2 sin t, y = 3 cos t as t varies in the interval 0 t 2 . 1. Moves once counterclockwise along the ellipse x 2 4 + y 2 9 = 1 , starting and ending at (0 , 3). 2. Moves along the line x 2 + y 3 = 1 , starting at (2 , 0) and ending at (0 , 3). 3. Moves once clockwise along the ellipse x 2 4 + y 2 9 = 1 , starting and ending at (0 , 3). correct 4. Moves along the line x 2 + y 3 = 1 , starting at (0 , 3) and ending at (2 , 0). 5. Moves once counterclockwise along the ellipse (2 x ) 2 + (3 y ) 2 = 1 , starting and ending at (0 , 3). 6. Moves once clockwise along the ellipse (2 x ) 2 + (3 y ) 2 = 1 , starting and ending at (0 , 3)....
View Full Document

Page1 / 13

HW 6 - wolz (cmw2833) HW 6 ODELL (54615) 1 This print-out...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online