# tut8_sol - EE 4212 Information and Coding Solution to...

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1 EE 4212 Information and Coding Solution to Tutorial 8 Q1(a) Transmission Rate = 19200 coded symbols/s Contiguous noise burst lasts for 250 ms. Ö Coded symbols affected = 19200 x 0.25 = 4800 d min = 31 and so 15 2 1 31 = = t Number of blocks to share all the error bits = 4800 / 15 = 320 blocks After deinterleaving at the receiving side, 15 out of 127 coded symbols in a received block are in error. They can all be corrected as t =15. Block Interleaver : 15 error symbols 320 blocks n = 127 total 4800 error symbols a block consists of 127 coded symbols

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Q1(b) Transmission Rate = 19200 coded symbols/s Contiguous noise burst lasts for 20 ms. Ö Coded symbols affected = 19200 x 0.02 = 384 Number of blocks to share the error bits = 384 / 3 = 128 blocks After deinterleaving at the receiving side, 3 out of 21 coded symbols in a received block are in error. They can all be corrected. Block Interleaver :
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## This note was uploaded on 02/26/2011 for the course EE 4011 taught by Professor Wadewe during the Spring '11 term at City University of Hong Kong.

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tut8_sol - EE 4212 Information and Coding Solution to...

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