MT1sol - Stat202 Fen 2010 STAT 202 - Fall 2010 — Test 1 -...

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Unformatted text preview: Stat202 Fen 2010 STAT 202 - Fall 2010 — Test 1 - Question Booklet Part 1 - Measurements were performed at a buoy in the Gulf of Mexico in June of 2010. The measurements were made at 3 locations, in Fahrenheit: 1 2 Sea (surface) Temperature, 2 = Air Temperature, 3 : Dew point (the termperature at which an amount of humid air turns to water). Temperature in Degrees Fehrenheidt for 2010 90 100 110 Frequency 80 1 2 3 Measurement Location A plot of just Sea Temperature, in Fahrenheit, for June 2010 follows: The decimal paint is 1 digit ('3‘: to the right of the I 1256 IR] ! i 10! 1 1390131 at R Stat202 I%012010 A plot of just Sea Temperature, in Celsius, for June 2009 follows: SeaSurfaceTemp, 2009 10 ‘RT :5... if") Q C G) 3 U 9 LL N I 0 10 20 30 40 50 Sea Surface Temp A plot of just the Dew Point, in Fahrenheit, for June 2010 follows: The decimal point is at the I '70 I 45 '72 | 9 I 345 75 l 2239 75 | 0156 7'? l 224 Pam: ‘2 n? R Stat 202 Fall 2010 Multiple Choice Questions: Please respond with the most correct answer in the spaces provided on the answer sheet; answers that are not transfered to the answer sheet will not be graded. Unclear answers are marked wrong. No marks are taken off for incorrect responses. Each question is worth 1 mark. Question 1: For the Sea (surface) temperature measurements of 2010, the whisker of the corresponding boxplot is: A) 112 B) 11.2 C) 1.12 D) 0.112 E) 0.86 F) 8.6 G) 86 H) A value between G and A I) A value between F and B J) A value between E and C K) None of the above Question 2: The single outlier for the 18, 2010 Dew Point data, is x IQRS below the third quartile, where x is... A) 0 1) None of the above Page 3 of 6 Stat 202 Fall 2010 Question 3: It is obvious from the boxplot for air temperature that... A) Air temperature has a bi modal shape. B) That the mean is less than the median. C) That there is more than one outlier. D) That there are 15 data points. E) None of the above are obvious from the boxplot. Question 4. You could argue that there is a distinct difference between the Dew Point temperature and those of the Sea and Air. A) True. B) False - there are too many outliers to make the decision clear. C) False - there are too few points to make the decision clear. Question 5. The removal of the outlier in the Dew point data will affect which statistic the most? A) Median B) Q1 C) Q2 D) Q3 E) Mode F) Mean G) None of the above. Question 6. Unrelated to the story above. Event A and B are such that Pr (AB) = Pr(A) > 0; Pr(B) > 0 A) A and B are Mutually Exclusive and Independent B) A and B are not Mutually Exclusive and Independent C) A and B are Mutually Exclusive and not Independent D) A and B are not Mutually Exclusive and not Independent E) A and B are Disjoint and Independent G) A and B are Disjoint and not Independent H) Both E and A I) None of the above. Question 7. Unrelated to the story above. Event A and B are such that Pr (AIB) = Pr(A) > 0 A) A and B are Mutually Exclusive and Independent B) A and B are not Mutually Exclusive and Independent C) A and B are Mutually Exclusive and not Independent D) A and B are not Mutually Exclusive and not Independent E) A and B are Disjoint and Independent G) A and B are Disjoint and not Independent H) Both E and A I) None of the above. Page A of (i Stat 202 Fall 2010 STAT 202 - Fall 2010 — Test 1 — Answer Sheet Family (Last) Name: Given (First) Name: ID Number (i.e. 20101010): User ID (Le. jsmith): Aids: Non-Programmable, Non—Graphical Calculator. Part 1 [7 Marks] Please write the most correct answer to the multiple choice questions in the spaces provided to the right of the question number below. 1. G 2. H 3. E 4. A 5. F 6. B 7. Other answers which were accepted: 1. K — it was unclear which whisker was of interest. 2. I - dependent on rounding. 6. I — dependent on assuming Pr(B)=0. Part 2. [18 Marks]. Answers will be graded based on their completeness. 1. [8 Marks] Notice the marks! This question refers to the plots on the question sheet. Using exact values where possible and approximate values ONLY where necessary, compare the spread of the 2009 and 2010 sea surface temperatures. 5 $z’ E : (formula) = 812 + 822 + 852 + 862 + 1122 5 1:1 __ 81 + 82 + 85 + 86 + 112 = 404500 _ 5 = 89. 2 [1] Z5 x? — 5 (a)2 s 52 = [1] (formula) CV2010 = E [1] (formula) 40450 — 5 (89.2)2 : V 1"“ = —T—— 89.2 : 166.7 [1] : 0.144 74 [1] 2009 s m 50/6 2 8. 333 35:5 e 25 [1] C V2009 = S % 8.3 55— I 0.332 [1] (s is range over 6; x bar should be 25; 15 is median BUT skewed) [1] Therefore the 2009 data is more spread out than the 2010. Pan‘p 5 at H Stat 202 Fall 2010 2. Be sure to Show all your work, and clearly define your events. Lesch—Nyhan syndrome (LNS) is a genetic disease we believe passes from mother to child. You will either have the disease (D), be a carrier (C) for the disease or not have the disease Observations on 299 single child families have noted the following: Table 1 Table 1 is read as follows - in 22 families a mother and child were both carriers of LN S. (a) [3 Marks] What is the probability that a randomly selected single child family has a mother who is a carrier or a child who is a carrier, but not both? Let CM and 00 be a mother and child carrier respectively. [1] Pr (CM U 00) : Pr (CM) + PI (Cc) — ZPI (CMCC) [1] _ 1%. + a _ 2 2 H 299 299 299 2 0.2107 [1] (b) I draw a sample of size 2 from the families, with replacement. 1. [3 Marks]What is the probability that family one has a mother with LN S and a child who is a carrier for LNS while the second family selected consists of a mother and child with LN S? Let D be the first family and C be the second family. [1] Pr(CflD) = Pr(C')Pr(D) (assume indep) [1] 89 12 = (aha) = 1.1946% [1] 2. [2 Marks] How does your answer to change if we don’t know which family, of the two defined in (i), was the first selected? Pr (0 n D OR D n C) = Pr (CD) + Pr (DO) {1] _ 2 a a — 299 299 = 2. 389 2% [1] 3. [2 Marks] How does your answer to change if we use sampling with replacement? Pr (0 H D) : Pr (0) Pr (DIG) (assume indep) [1] _ 2 a ~ 299 298 = 1. 198 6% [1] Pawn F. nf Fi ...
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MT1sol - Stat202 Fen 2010 STAT 202 - Fall 2010 — Test 1 -...

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