bonding - Petrucci 10th ed Problem set #4: Chemical bonding...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Petrucci 10 ed Problem set #4: Chemical bonding 1 of 7 th Petrucci 10 Edition problem set #4: Chemical Bonding th Chapter 10 10.3 a) b) c) d) e) 10.4 a) b) c) d) e) 10.11 a) incomplete octet around C b) incomplete octet around left C and not enough valence electrons in the structure c) this Lewis structure is correct d) too many valence electrons in this structure 10.17 a) FC(H) = 1 – 0 – 1 = 0 FC(central C) = 4 – 0 – 4 = 0 FC (terminal C) = 4 – 2 – 3 = -1 b) FC(C) = 4 – 0 – 4 = 0 FC(-O) = 6 – 6 – 1 = -1 FC(=O) = 6 – 4 –2 = 0 c) FC(H) = 1 – 0 – 1 = 0 FC(central C) = 4 – 0 – 3 = +1 FC (terminal C) = 4 – 0 – 4 = 0 10.18 a) FC(I) = 7 - 6 - 1 = 0 b) FC(S) = 6 – 2 - 3 = +1 FC(-O) = 6 – 6 - 1 = -1 FC(=O) = 6 – 4 - 2 = 0 c) FC(N) = 5 – 1 - 3 = +1 FC(-O) = 6 – 6 - 1 = -1 FC(=O) = 6 – 4 - 2 = 0
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Petrucci 10 ed Problem set #4: Chemical bonding 2 of 7 th 10.21 a) FC(O) = 6 - 2 - 3 = +1 b) FC(Al) = 3 - 0 - 4 = -1 c) FC(Cl) = 7 - 2 - 5 = 0 d) FC(Si) = 4 - 0 - 6 = -2 e) FC(CI) = 7 - 4 - 3 = 0 10.22 b) FC(S) = 6 - 4 - 2 = 0 FC(C) = 4 - 4 - 2 = -2
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 02/26/2011 for the course CHEM 1000 taught by Professor Hempstead during the Spring '09 term at York University.

Page1 / 7

bonding - Petrucci 10th ed Problem set #4: Chemical bonding...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online