Sp08_MT1

Sp08_MT1 - BIPN 102, MAMMALIAN PHYSIOLOGY 11 NAME: 5691...

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Unformatted text preview: BIPN 102, MAMMALIAN PHYSIOLOGY 11 NAME: 5691 Spring 2008 lst MIDTERM EXAM I.D. # April 25, 2003 1. (10 points). Write the sequence in which the following events occur during inspiration: (points will be given only up to the first wrong event in the sequence). A) airflows into lung C 73 ___? E ab __7A. B) transpulmonary pressure increases /. C) diaphragm contracts ' M D) alveolar pressure decreases E) alveolar volume increases 2. (12 points). Fill the following table with increased, decreased or normal for the following parameters of patients with the indicated diseases: Obstructive (e.g. emphysema) Restrictive (e.g. fibrosis) Com liance \ t mm. l Jet-raised Residual volume _ l I. r 7 3. (8 points). Imagine a world 10,000 years from now where humans have evolved drastically; we’ll call this new species Homo sapiens sapiens sapiens. Their respiratory tracts are now twice as long and twice as wide. By what factor would this advanced individual have to increase or decrease the pressure gradient to maintain the same air flow as individuals of today? Show your calculations. . 1:29“): 1110qu , ' ~2er Art/e \l\\t>\>\ jz:2[ AP Wow ch/eas‘f '8)! A meme OF E l 4. (8 points) A La Jolla Shores Beach Lifeguard is giving mouth to mouth respiration to a girl that \Zlmost drowned. List below the expected values of the P02 and PCOZ with the correct units in his xpired air at: P02 PC02 g? the beginning of expiration: [5b in m #13 ~ 0 m m #6 the end of expiration: / 00 mm A? [7/0 "W BIPN 102, MAMMALIAN PHYSIOLOGY 11 NAME: K‘E 2 Spring 2008 lstMIDTERM EXAM 1.1). # April 25, 2008 5. (12 points) a) Assuming the above diagram are the alveoli of a very premature baby, draw the direction of the local airflow (towards the left or ihe 25m alveolus) if the alveoli are; allowed to equilibrate. Why? W L. _ V, air/es V6 [‘4' her rasva “4 5W , \M Aim. of/ peJL al/yWS’ecr s We - Ma “47% WW I??? nan b) In a normal a ult there would be no net air flow between the alveoli. Explain why, using the Law f 7 LaPlace. Assume the left alveolus has a radius 1/3 smaller than the right one. Which alveolus will have a higher surface concentration of A ' _ 1 g _‘ a Lpdj ’- ' til} , v ‘ ' 214 Fe. ' i r» in 5 m + m” w 7% Wm ’ :27 \9 Mi QM ' L ' m W “W l“ M Q CWC k 94,, m 5 Va . c)‘ List the main co ponent ff surfactant and the chemical property that allow surfactant to do this. a :DPPC (a .- p.19 .4393 fhst/du‘ém .. [clawing/if: vial 74w 4 WM Q WK , W/wb “HQ/fad NZJMCfl/J/ 04/20 a a *9“? J SW'Q+WIGH1_ 6. (8 points). In preparation for a half-marathon you’re exercising in Mexico City at an elevation of 2, 240 m, where the atmospheric pressure is 570 mm Hg. You carbo load (100% carb diet) for a week prior to the race. What will be the P02 in your trachea and in your alveoli assuming your alveolar PC02 is 20 mm Hg because you are hyperventilating? Show your work and round-off to the nearest it . , :eger PM :(Pah— PM...) 0.21 : (WWW-U : 523x011 = #0 w \c" .0" - ,. , FPO} ,_ ou-Efl’ fi‘bmm , (bi PAOZ ,, Pia: ARL ‘ H I _ 7. (8 points) During a BIPN 102 midterm exam a student with normal lungs becomes very nervous. His normal total ventilation is 6L/min with 12 breaths/min, but nervousness increases his frequency to 42/min. What must be his tidal volume to avoid changing his alveolar P02 and Pcoz ? (4-:CVflD' VDEAP)XW£3 : (m I ' an:er 3R +0 waif/2‘54 92M w)“ ’ rec \Ls so meibe.~250m13 BIPN 102, MAMMALIAN PHYSIOLOGY 11 NAME: If Spring 2008 lst MIDTERM EXAM I.D. # April 25, 2008 8. (12 points) Several scientists and study subjects ascend/descend to a particular altitude to conduct experiments. The following experiments take place immediately following this ascent/descent. Please answer the questions regarding this graph shown below: O .25 .50 .75 Tm h w (ICC? A. What is the PM here? What about P602 7 :63: l a v E § B. Scenario X: a normal subject is at rest. Scenario Y: a normal subject exercises such that the cardiac output increases by a factor of 5. Scenario Z: an anemic subject is at rest. Indicate whether the scenario is perfiisgllimited or diffusion-limited. Do not abbreviate. l X= EM lOM’ %m Y= iffmrw- mu Z: flrstM-LMJCJ“ C. Curve A reflects normal gas exchange at this particular altitude. Which curve corresponds to that of an anemic person? . I I, A 7111 )1 a . P CW A, line ' cleavages DZ-WN-Jmi (e “"41; H W M W 02 "Mar Ff‘J/MW . 9. (12 points) In the 1970’s it became popular to “meditate” while standing on one’s head against a wall. Indicate how the following values change during this action with either an up arrow (T) increase or a down arrow (i) decrease. Top = top of the lung in a normal upright subject. Ventilation _ — perfusion __ V/ ratio —-‘_ Alveolar Com liance -—_— -—-— Diameter of arterioles Diameter ofbronchioles _-—— BIPN 102, MAMMALIAN PHYSIOLOGY 11 NAME: / 2 Spring 2008 lst MIDTERM EXAM I.D. # April 25, 2008 10. (10 points) The graph below shows Hb-oxygen dissociation curves. Curve 2 is the normal adult hemoglobin. 100 4» CM La“ MGKC'tlJe SS OZSaturation of Hemoglobin 010 2030405060708090 pozmmHg A. List 3 different conditions that can cause a shift like curve 3. t , l PH, t mpg, Mempewlw (M3 3 WM) B. What type of hemoglobin shows behavior like curve 1? 75¢in He b m C. Draw in the above graph the expected curve for a person intoxicated with CO that bound to one of the hemes of all Hb molecules. 11. (8 points).A. Indicate if the chloride concentration in the plasma of the pulmonary artery is higher, §lowen or the same as in the plasma of a pulmonary vein: L U Em Pulnoman/ VEN/ LDWEIQ (N /PULHONA/Ey 14/5397 B. Explain or diagram the mechanisms that justify your answer. Hint: think of C02 transport. CO (ii; ' may) im‘ib R44 Mac-J Cells II/n ’i’lSSUQ (dial/[miefi/ r6409 wzfii (flan/m #ZCOS (Co‘s/hem? dhAjdro’Se veac+lom>l #26623— ciA/IMOCZQZQ [4333- Kata/«Mtge; (fl/7% So W (1’1). “70 ( i/7ZC05 geese 7" 23 #0 p/as‘ma. [Panama dw/é/rllef % L:a[C€3W WAS/«4 '~ 2, slam #76 Fm raw! 5am 71mg uf Alf/hi7; f (‘4 Inevan én fwfmswu in ppm D.) / ...
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Sp08_MT1 - BIPN 102, MAMMALIAN PHYSIOLOGY 11 NAME: 5691...

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