ME80 - Homework 3 Soln

# ME80 - Homework 3 Soln - HEXO 4-1007 Aim#3 504,475 A T'T...

This preview shows pages 1–6. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: HEXO 4-1007 Aim/#3 504,475,) A T 'T 6:44 ﬁt Vie/45W ‘h‘a 3%? meé/é’m l / ‘V/hpmﬁxre = T 0"”. fp— a|~ LﬁmeM-ﬂf :mc (a) RﬁCa” £17m ’IYEMIIG‘ 'n 017“ MC __ — _ r P ’ an C20“! 012‘ me? if 6%,, “ 147- 50 L670 {ace Wig/“n1 Mei—(5) + 14775) c at), (s) w; M 28/0 I‘m 0‘ C¢O¢/J"J7(3nj .' 50 (3(5): :12 __ I OMS) ‘ I’MFSJ-l, I: 1': () Mat)“: Ki «(rm + k6, iii/ﬂaw» L6? /QC(’ Mfg/m 2&0 2‘0 rhhté/ (0r) .' st>= ’2 L WM 50 Maw 2667 Him-tr? so/m‘m gob-aw) If ﬁégém 2 (a) If 52(31): I - ‘L (Ly/(«Q 74%)74077 071‘ <4»er Luge) -t ,r 77*): OZ”— f'm): =02 (mgwsg fw‘fa/ 4%«5‘0’1 exfwfoﬂ: 4;, z ,4 is (mcps+A)S mg”) + J 1 A5 + 507925”) emwe 4% Pas/P i=0 33""3: I: 317 => LET 4‘ 1, "06 ll Pdvawk 4+ fwk 5:: - _f ‘mco ‘ TVS Ta): 4 m95+h S -l __l/A : of M’L 75 ij—):// U(S):_§l__ Em ﬂag/m, [(4) X8): 6(5) (/6) = (kF+K0/5+_If£),4 S 5 _ l< \$0 X(5)" {+Ka,+ {2 wk” 50);) %e ole/Ja—ﬁﬂcﬁbn. Pnai/em 3 ‘_____—.. (a) 101' conﬁne/{tr fC’J/owf Jo a um‘f ramp (>1 error .' f.— wok-1k? + f3 .1135) I 6(5) : £§15§= Z;- ..L {I 53 k 1 -I 1" 44m; A”): x {Um kpt*;}’t 50 L18) : :16 + (Gabi/c" +0 4 am“!— amf )4 {’F/o/ .’ “(9" {'8“(kr+ke§s>';‘a§= z" ‘3}? 44m VHF kft + 5,7; l “p .7} 3“ 1 B-w-3—1 . W ,,,,w__________ W“——_m__—— 3—3—5- when D(s) is zero, the closed—loop transfer function CR(s)/R(s) is cm) _ 62 (r) w!) 2m 2+ 4:0“) 6;. (I) When Ris) = 0, the closed—loop transfer function CD(s)/D(s} is C3M5) n / ms) ‘ 1+ 6d!) (us) When both the reference input and disturbance input are present, the output C(s) is the sum of CR(S) and CD(5). Hence ((5):: CR {5) +— Cp(;) 2.: Mg m6 3) [66(5) Gina) kg) «4- 19(5)] c f .__......_._.______...M,._._______._.__.______..____....._._.-.__..__..—.._——.—___...-m..———.—__—————_.....-—.—.——- 9—3—7- When NS} = 0, the block diagram of the system can be simplified as follows: The closeddoop transfer function CR(s)/R(S) can be given by 6: (if (73 C71 CRIS) __ (+5, (51 #1 ﬂ. (5:: 5t 52 6; W 1+ _____.._‘?c ‘9'62 ‘5: #2 2+ 6,6: m + 5m, (72 4mg "1" 51 61 HI when Me) = 0. the block diagram of the system shown in Figure 3—76 can be modified as follows: Hence CD 6’ 63 (51 C73 1i ...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern