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# work - Example problems The mass = 80 Kg man in the figure...

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Sheet1 Page 1 Example problems The mass = 80 Kg man in the figure is bench pressing a barbell of mass 100 kg. Assume that the mans feet are lifted slightly from the floor so that the normal force from the floor on his feet is always 0 N. Force of the bench on the when he is holding the barbell in fixed position: Fb - M2g - Fbb = MlAl = 0 Fb = Mbbg + M2g = (80 + 100)(9.8) = 1764 N Force of the bench on the man whne he is accelerating the barbell upwards, 2 m/s^2 rate: Fb = Mbb(g + 2 m/s^2)+Mlg = 80x9.8 + 100x11.8 = 1964 N Accelerating barbell downward at rate of 2 m/s^2 Fbb = Mbb(g - 2 m/s^2) Fb = [80x9.8+100x7.8] = 1564 N Two Blocks of mass M1 and M2 are being accelerated across a horizontal surface at an unknown rate a. THe blocks are connected by a string with unkwon tension T2 and an external agent pulls on a string attached to th first block with a known tension T1. THe first block experience no frictional forces, but the second has coefficients of friction Us and Uk. Express your answers in terms of M1,2, T1, g, Us, Uk.

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work - Example problems The mass = 80 Kg man in the figure...

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