PS5-08 - noted(60 points b How would your design change if...

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HO #21; 10/24/08 CE 166 Construction Engineering Fall 2008 Problem Set 5 Total: 100 points Due: November 5, 2008 1. a) Design forms for an 8 ft-high, 12 ft-long concrete wall to be poured at a rate of 7 ft/h, internally vibrated, at 110° F temperature (similar in arrangement to Figure 13-3 on p. 391 of the textbook). C w and C c are 1.0. C d does not need to be taken into account. Sheathing will consist of 4x8 ft sheets of 3/4” thick Class II Plyform with face grain perpendicular to studs. Studs and double wales will be made of 2x4” lumber, but you only have 500 lineal ft of 2x4s available. There must be studs at the corners and wales at the top and the bottom of the form on both sides of the form. Snap ties are 2,000 lb capacity with 2” wide tie wedges. Deflection must not exceed l/180. All spacings need to be the same along the length and height of the wall. Determine stud, wale, and tie spacing. The allowable stresses for the lumber for studs and wales are the same as for average Southern pine lumber. Draw a sketch of your design with the spacings
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Unformatted text preview: noted! (60 points) b) How would your design change if 5/8” thick Class I Plyform became available at the same price? Would you recommend buying Class I Plyform instead of Class II if Class I was more expensive? Show your calculations. (15 points) 2. Determine the maximum spacing of nominal 2x4 lateral braces for a wall form similar in arrangement to Figure 13-4, p. 398 of the textbook. Braces will only be placed on one side of the form. The height of the form is 7 ft, the height of the top of the brace is 5.5 ft, the horizontal distance from the form to the bottom of the brace is 4 ft. The wind force prescribed by the local code is 15 lb/ft 2 . If you determine that braces are prone to buckling, use lateral support to each brace at the midpoint of its length. The 2x4 braces are made of Eastern spruce for which the modulus of elasticity was found to be higher than usual, 1,400,000 psi. The allowable stress values are: F c = 700 psi F t = 625 psi (25 points)...
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