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# lab2ce301 - Matt Lavis CE 301-Section 15515 Lab#02...

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Unformatted text preview: Matt Lavis 1/31/2011 CE 301-Section 15515 Lab #02 Assignment-Introduction toExcel Problem 1 Moment of Inertia Equation: I= (1/12)bh3 Deflection Equation: δ=PL3/48EI a) idth (b) = W Height (h)= Length (L)= Modulus of Elasticty (E) = Moment of Inertia (I)= 1.5 in 0.75 in 36 in 1600000 psi 0.05 in4 Load "P" 5 10 15 25 50 Load "P" 5 10 15 25 50 Load "P" 5 10 15 25 50 Load "P" 5 10 15 25 50 b) Width (b) = Height (h)= Length (L)= Modulus of Elasticty (E) = Moment of Inertia (I)= 0.75 in 1.5 in 36 in 1600000 psi 0.21 in4 cWidth (b) = ) Height (h)= Length (L)= Modulus of Elasticty (E) = Moment of Inertia (I)= d) idth (b) = W Height (h)= Length (L)= Modulus of Elasticty (E) = Moment of Inertia (I)= 1.5 in 1.5 in 36 in 1600000 psi 0.42 in4 1.5 in 1.5 in 60 in 1600000 psi 0.42 in4 Deflection of a wooden beam 0.7 0.6 0.5 0.4 0.3 0.2 0.1 0 Loa d "P" lbs D e f le c t io n " δ" ( in ) 0.06 0.01 0.01 0.03 0.12 0.03 0.01 0.07 0.17 0.04 0.02 0.1 0.29 0.07 0.04 0.17 0.58 0.14 0.07 0.33 0.4 0.3 0.2 0.1 0 Loa d "P" lbs o n " δ" ( in ) 0.1 0.29 0.07 0.04 0.17 0.58 0.14 0.07 0.33 Deflection 0.7 0.6 0.5 0.4 0.3 0.2 0.1 0 0 10 20 D e f le c t io n " δ" ( in ) Loa d Deflection 0.06 0.12 0.17 0.29 0.58 Deflection "δ" (in) 0.01 0.03 0.04 0.07 0.14 Deflection "δ" (in) 0.01 0.01 0.02 0.04 0.07 Deflection "δ" (in) 0.03 0.07 0.1 0.17 0.33 beam 0.06 0.01 0.01 0.03 0.12 0.03 0.01 0.07 0.17 0.04 0.02 0.1 0.29 0.07 0.04 0.17 0.58 0.14 0.07 0.33 0.7 0.6 0.5 0.4 0.3 0.2 0.1 0 5 D e f le c t io n " δ" ( in ) Deflection of a wooden beam 10 15 25 50 0.1 0.29 0.07 0.04 0.17 0.58 0.14 0.07 0.33 0.4 0.3 0.2 0.1 0 5 10 15 Loa d "P" lbs 25 50 Deflection of a wooden beam 0.7 0.6 0.5 0.4 0.3 0.2 0.1 0 0 10 20 30 40 50 60 Loa d "p" lbs Column G Column G Column G Column G D e f le c t io n " δ" ( in ) c t io n " δ" ( in ) wooden beam Column G Column G Column G Column G 25 50 Column G Column G Column G Column G 25 50 ...
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