121ss06m2_sol - Phy 121 Spring 2006 Midterm 2 Solutions:...

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Unformatted text preview: Phy 121 Spring 2006 Midterm 2 Solutions: Exam A=B=C=D 1. (1) (D) R GmM /- (2) (E) ) /( h R GmM +- (3) (C) 2 1 / 2 GmM R mv- + (4) (A) 2 1/ 2 ' /( ) mv GmM R h- + (5) (E) 2 9 1 ' / /( ) 2.9 10 2 mv GmM R GmM R h J +- + + ( 6) (C) 2 9 1 ' (1/ 1/( )) 2.9 10 2 mv GmM R R h J = +- + + = 11 24 2 9 9 6 1 6.67 10 12000 6.0 10 12000 580 (1/ 6.4 1/(6.4 0.5)) 2.9 10 59.3 10 2 10 J J- = + - + + = 9 2 2 59.3 10 3144 / 12000 KE v m s m = = = 2. (7) (B) The total momentum is conserved (8) (B) The total mechanical energy is conserved (9) (D) ( ) ' mv m M v = + (10) (A) 2 1 ( ) ' ( ) 2 m M v m M gh + = + (11) (C) 2 2 2 2 1 1 0.085 61 ( ) ( ) 0.26 2 2 0.085 2.2 9.81 m v m m M g = = + + 3. (12) (D) 2 1 2 MR (13) (A) 2 1/ 2 MR (14) (E) t (15) (C) 2 2 1/ 4 M R (16) (C) 2 2 2 2 2 2 2 2 2 2 2 1 1 2.3 4.7 ( ) ( ) 818.1 4 4 2.7 0.23 rot t KE MR t MR t J MR MR = = = = = 1/2 1 4....
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This note was uploaded on 02/27/2011 for the course PHY 121 taught by Professor Stephens during the Spring '08 term at SUNY Stony Brook.

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121ss06m2_sol - Phy 121 Spring 2006 Midterm 2 Solutions:...

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