20102ee10_1_ee10_hw1_solution

# 20102ee10_1_ee10_hw1_solution - power so the power must be...

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EE10 Homework 1 solution Due 4/7/2010(Wed) P 1.14 Assume we are standing at box A looking toward box B. Then, using the passive sign convention p = -vi, since the current i is flowing into the - terminal of the voltage v. Now we just substitute the values for v and i into the equation for power. Remember that if the power is positive, B is absorbing

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Unformatted text preview: power, so the power must be flowing from A to B. If the power is negative, B is generating power so the power must be flowing from B to A. [a] p = -(125)(10) = -1250 W 1250 W from B to A [b] p = -(-240)(5) = 1200 W 1200 W from A to B [c] p = -(480)(-12) = 5760 W 5760 W from A to B [d] p = -(-660)(-25) = -16,500 W 16,500 W from B to A...
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20102ee10_1_ee10_hw1_solution - power so the power must be...

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