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Unformatted text preview: Physics 222 ABC EXAM #3 (Chapters 2832) FAIj 2 7 Name. :37  ' Instructions: For the appropriate problems circle the letter corresponding to the correct answer. If you are sure that no correct answer is shown, you should write your answer in space (i) . Some questions require ﬁlling the blanks. Note
that some problems/questions have more than one (1) correct answer. For those problems/Questions you should give all the correct ers. The numbers in the [ ] represent the points for the problem. L/Uél: 1. ' tching: Write the letter of the items on the right in the space in ﬁ'ontAoyhe correct answers on the leﬁ. ( a mass—spring system, M (kg) corresponds to . L (H) inductance
( 0 w a massspring System, v (m/s) corresponds to ,8/ 4,; = eh/4‘rtm
O ( f massspring system, x (m) corresponds to . ,5 S2 = Irish/2n, m5 = (+/)(1/2)
( e 2 component of the electron’s orbital angular momentum D _. 1/C. (I?)l Capacitance
( O, « ' e 2 component of the electron’s spin magnetic quantum number /E’ Q_(C) éléctric charge
( E) Bohr magneton ,l/ \ i (A)‘current
( F )ﬂln a massspring system, the spring constant k (N/m) ﬁ/ Lad” = Huh/21:, m; = 0, (+/)l, (+/)2, ..., (+/)m max.
. corresponds to ‘ '  ' . * ' {/[6] 2. A fully charged capacitor is connected in parallel with an inductor using wires that have some res' ance. The ci
now begins to oscillate. Circle each 2S the false statements below? (Note that there are more than one 
Answers: (a) This is an example of a amped oscillator. This is. an example of an undamped 0s
will continue indeﬁnitely (i.e, for ever). (d) Energy will e lost during each cycle of the oscillati
eventually stop. ,(e) Itis possible to keep the oscillations going indeﬁnitely Ewing an alt ating emf source that has the right i
voltage amplitude and frequency, in series with the capacitor and inductor,. or the cir t the in uctive reactance will
always cancel out the capacitivereactance to give resonance. 2 .. K 2 +( X L: X C (4% .— EI : It, / .
\,/_For the RLC circuit at the right R = 7.80 Q, C = 820 pF, L = 1.50 pH, and £0) = 87.0Vsin [21t(7.3 NIHz)t]. Use
this informationto answer problems 3, 4, Sand 6. $349 I Q in"; V ;TO X Q , ,
[8] 3. Wire the impedance resulting ﬁom R, L and C in the circuit C.“ ‘1 l R L
Answer: .XL=37.O Q, XC=33.0 O. (b). XL=78.0’Q, ‘XC=53.OQ c —
mtg/(cfoyo, XC=47.OQ. (d).XL=69.OQ, Xc=27.0Q. Wm? ! Q J
. t) 'X= on, Xc=19.0Q. (r) :_
L 3536 ‘ Z [8] 4. Determine the phase angle td complete the following statement: ‘ { $20 1‘ “9
/ The current in t circuit is given by i(_t) = 87.0V siVMHzﬁ  4)], 005 6 2. 8m
. 1 _ I Answer: (a) 10.0”. 80.00 (c) 650" (a) 37.0°[email protected]‘8.o°y ' (a 4
. [5] 6. Whi h of t
Answerszé phasor diagrams below would best describe the current and voltage relationships ofthecircuit'inprohlem 3?
8 VR . (b) VR . (c) ' VR 8 . (d) VR VL a t/ (and a a [10] 7. The magnetic ﬁeld through the semicircular loop (radius is 25.0 cm) . . . . .
changes according to the relation B(t) = 6.9t3  4.0t, where ﬁt) is in mT. _ x ‘ .I ' ‘ 2 ‘
and t is in seconds; The resistance of the loop is 8.40 mg. Q0 ,‘H " Li’ 0 .
‘ ' 1010.3 What is the magnitude and direction (circle the correct choice) of the
current that is induced in the loop at t = Physics 222 EXAM 3 SPRING 2007 A Name: [11 ,9. Match the equat' :15 in problem 8, with the statements below by writing the letter of the equation in 6:1? by the correct temen (s). .
State nts: ! z This is a ﬁctiti 3 current (i.e., as current betwee th 1 es of a capacitor). Strjgéts that
elec 'c charges can be of two typesxrzning the same mag. ude of char e Gauss’s Law for electrostatics.
Farraday's Law. i pereMaxwell's w. (i Gauss's Law for gnetism. g Predicts that no is l ted magnetic monopoles exist in nature. A changing magnetic ﬁeld produces a electric ﬁeld. C 5 A changing electric ﬁeld produces a magnetic ﬁeld. f uggests that isolated electric charges 0 be found in nature. ﬂ 3 suggest that there is a connection between light and electric and magnetic ﬁelds. in nonsense. _ . ‘
d3 3 ,qo Lde smé} R L” . air
(4 [6] 10. A 6.50 12 sistor and 870 pH inductor are connected in series across an ideal
battery that suppl' 5 13.8 VﬂIow much energy is stored in the m etic ﬁeld of the inductor when, L
the magneti ﬁe becomes stable? \. 1 R 1 O? . i Z i )
Answer: ' O‘mJ. (b) 1.10 ml (c) 4.50 m] (d) 9.60 m]. (e) 5.60 m]. (t) +  , J.  '2. .
H66 11'9“ ; ,gT—T—ML“
L4 [20] 11. A piece of wire is bent in the shape shown (a straight part AB 26.0 cm long, and a circular part
BDC of radius 37.0 cm). The wire carries a current of i = 3.0 A in direction of the arrows. '
Determine the magnitude and direction of the magnetic ﬁeld‘at point P; thccenter i'
of the circle, due to the Current in ABD—C. (Treat the circular pan as a' MA.
complete circle and. neglect the lead ﬁ'ofn endC1) F—‘leam 9 Hint: Break the 3 re into 0 parts and use the Principle of Superposition.
Answer: @‘.1 at )2.5 at. (c) 6.0 at. (e) 8.8 pr. (1) (d 6.9uT. _ L V 7’ ' QIS"
D' ct‘ ; In Q { L7. ﬁg; [57%. __ 7/1940) ,,___
ire 1011 Jig 0 “Tx [OIL I'Ilol 3.0H T113011" b.43/ [5] 13. The ﬁgure at the right shows a long straight wire and a conducting circular loop that are laying on the top of a table. The straight wire carries a current that is decreasing. ‘tr’ .
/ An induCed chrrent will be Set up in the ‘condUcting loot). The direction of the magnetic ﬁeld at P, 4‘ . i the center of the circle,‘due to this induced current '
Answer: (a) There is no magnetic ﬁeld at P. (b) To the left. (c) To the right
(d) Perpendicularly out of the page. ‘ .P endicularly into the page. (i) For Problems 13 & 14 use the information below:
The ﬁgure at the right shows a cross section of a system of three concentric conductors: . '
a thick walled cylindrical conductor B of outer radius 25.0 cm and inner radius 2420 cm carrying a current’of 14.0A in the direction of arrow l,‘ a solid cylinder C of radius 12.0 cm carrying a current of 26.0A in the dir ction
of arrow 2, and the outermost conductor A with inner radius 32.0 cm an outer radius ' , 4 36.0 cm carrying 9.0 A in the direction of Arrow 3. A [5] 13'. The net‘ current’( agnitude and direction, using the 7 e 'i
Answer: (a) 1.0 A. (b 4.0 A. (c) 6.0 A. (d) 10 A. . _/ ln+;Ll1LQ+L5:
%]14. D ermine e magnetic ﬁeld (magnitude and direction) at a distance of 30.0 cm from the center of the solid cy nd ,
' 5 Answer: ‘2.  . (b) 7.6 tiT. (c) 2.9 uT. (d) 5.9 uT. (e). (d) 9.6 ttT. (i). ' . Direction: C100: '5 e. —.._.____— 1.3915 [12] 15. The ﬁgure shows a uniform magnetic ﬁeld. The lines represent
the paths taken byparticles that suddenly enter the magnetic ﬁeld.
Match the path number with the charge on each particle. 1+ . . . . , \ posrtr‘vi, egatrve, or n neutral) 5 l 2. ,
v I of the arrows) through the cross section shown is
A. (i) . Direction: In the direction of Arrow # 2, ...
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 Spring '11
 Henry

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