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Unformatted text preview: v = x R g 2 h = (10 m) r 10 m / s 2 2 (10 m) = 10 √ 2 m / s = 5 √ 2 m / s . 002 10.0 points A man can throw a ball a maximum horizontal distance oF 90 . 7 m. The acceleration oF gravity is 9 . 8 m / s 2 . How Far can he throw the same ball vertically upward with the same initial speed? 1. 45.35 2. 82.5 3. 62.0 4. 54.5 5. 69.0 6. 59.5 7. 66.5 8. 76.5 9. 90.5 10. 88.0 Version 022/AABBC – QTest #3 – Antoniewicz – (57380) 2 Correct answer: 45 . 35 m. Explanation: The range of a particle is given by the expression R = v 2 sin 2 θ g . The maximum horizontal distance is obtained when the ball is thrown at an angle θ = 45 ◦ and sin 2 θ = 1 . Solving for v , v = r g R . When the ball is thrown upward with this speed, the maximum height is obtained from the equation v 2 f = v 22 g h . Let v f = 0, and solve for h h = v 2 2 g ....
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This note was uploaded on 03/01/2011 for the course PHY 303K taught by Professor Turner during the Spring '08 term at University of Texas at Austin.
 Spring '08
 Turner
 Physics

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