Test Bank Ch.1

# Test Bank Ch.1 - Chapter 1: Introduction and Basic Concepts...

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Multiple-Choice Test Problems Chapter 1: Introduction and Basic Concepts Çengel/Boles - Thermodynamics: An Engineering Approach, 5 th Edition (Numerical values for solutions can be obtained by copying the EES solutions given and pasting them on a blank EES screen, and pressing the Solve command. Similar problems and their solutions can be obtained easily by modifying numerical values.) Chap1-1 Pressure Difference in Water (Submarine) Consider a submarine cruising 30 m below the free surface of seawater whose density is 1025 kg/m 3 . The increase in the pressure exerted on the submarine when it dives to a depth of 110 m below the free surface is (a) 480 kPa (b) 804 kPa (c) 1400 kPa (d) 144 kPa (e) 1100 kPa Answer (b) 804 kPa Solution Solved by EES Software. Solutions can be verified by copying-and-pasting the following lines on a blank EES screen. rho=1025 "kg/m^3" g=9.81 "m/s2" z1=30 "m" z2=110 "m" DELTAP=rho*g*(z2-z1)/1000 "kPa" “Some Wrong Solutions with Common Mistakes:” W1=rho*g*(z2-z1) "not dividing by 1000" W2=rho*g*(z1+z2)/1000 "adding depts instead of subtracting" W3=rho*(z1+z2)/1000 "not using g" W4=rho*g*(0+z2)/1000 "ignoring z1" Chap1-2 Pressure Difference in Water (Lake) Consider an 85-m deep lake. The pressure difference between the top and bottom of the lake is (a) 834 kPa (b) 85 kPa (c) 417 kPa (d) 1220 kPa (e) 2430 kPa Answer (a) 834 kPa Solution Solved by EES Software. Solutions can be verified by copying-and-pasting the following lines on a blank EES screen. rho=1000

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## This note was uploaded on 02/27/2011 for the course BUS 215 taught by Professor Thomassexton during the Spring '09 term at SUNY Stony Brook.

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Test Bank Ch.1 - Chapter 1: Introduction and Basic Concepts...

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