Unformatted text preview: 0.6^4 + (4 choose 3 )*(0.4^2)*(0.6)^3 + (4 choose 2 )*(0.4^4)*(0.6)^2 + (4 choose 3 )*(0.4^2)*(0.6)^4 + (4 choose 1 )*(0.4^6)*(0.6)^1 + 2*(4 choose 2 ) *(0.4^4)*(0.6)^3+ (4 choose 3 )*(0.4^2)*(0.6)^5 9. Desired probability = (.1*.45)+(.12*.35)+(.15*.2) . 10. Because (12 choose 1)* (11 choose 1)* (10 choose 1) orders the denominations of the 3 single cards. Since the denominator does not consider order we have to be consistent and not order the numerator and so it should be (12 choose 3)....
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 Fall '10
 KEENAN
 Conditional Probability, Probability theory, Bayesian probability, Bayes Theorem, State highways in Indiana, 1000K

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