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Unformatted text preview: Click to edit Master subtitle style 3/3/11 forces acting all of sum vector = = net net F a m F Object in Equilibrium: , , = = = = ∑ ∑ ∑ ∑ z y x F F F or F X direction: θ sin mg ma = θ cos r F r F W ∆ = ∆ • ≡ x F dx F W f i f i x x x x x x x tot ∆ = = ∑ ∫ → ∆ lim Area under the curve kx F x = 2 2 1 mv K ≡ i f net K K W = WorkKinetic Energy Theorem mgy U g = g net U W ∆ = 2 2 1 x k U s = ] ) ( ) [( 4 ) ( 6 12 x x x U σ σ ε  = ∑ = a m F net 3/3/11 f f i i U K U K + = + f f i i f U K U K W + = + + ] 1w 1watt [J/s = = ∆ ∆ = t W P v T P = A F p = flui d V M = ρ h g p p ρ + = h p g e p p(h) ) / ( ρ = g V Mg B cube f ρ = = Buoyant force 3/3/11 obj obj f f g gV gV F B ρ ρ = = f obj obj f V V ρ ρ = ⇒ constant v v v 2 2 1 1 = = A or A A Equation of continuity constant v 2 1 or v 2 1 v 2 1 2 2 2 2 2 1 2 1 1 = + + + + = + + y g P y g p y g p ρ ρ ρ ρ ρ ρ BERNOULL I Equation acts force which the...
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 Spring '11
 lalalalala
 Physics, Force

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