c103-sp10-0412 - Chemistry 103 Spring 2010 Today 1...

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Chemistry 103 Spring 2010 Today 1. Equilibrium for weak acids and weak bases. 2. More pH. Announcements 1. OWL homework for Ch. 14 is active. 2. ADD deadline on Apr. 12, Monday. 3. First midterm exam on Apr. 21. Chapter 14 (not 14.4-14.5, reverse osmosis) Chapter 15 (not 15.9) 4. CSULA closure on May 21 (furlough). 5. CSULA closure on May 31 (holiday). 6. Bring textbook and calculator to each lecture.
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Chemistry 103 Spring 2010 2 Review units Example : 0.63% by weight SnF 2 weight % = mass fraction x 100% 0.63% = mass fraction x 100% mass fraction = 0.63% / 100% = 0.0063 (grams of SnF 2 / grams of solution = 0.0063) molarity = moles solute / L of solution (Assume water is the solvent) Assume 100 grams of solution to simplify math. Assume solution is dilute enough that we can treat the 100 grams of solution as 100 grams of water => 100 grams = 100 mL = 0.100 L. mass fraction = 0.0063 grams SnF 2 1 gram of solution mass fraction = 0.63 grams of SnF 2 100 grams of solution
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Chemistry 103 Spring 2010 3 molarity = 0.63 g SnF 2 x (1 mole / 156.707 g) 0.100 L of solution molarity = 0.040 M 1 ppm = 1 g solute / 10
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This document was uploaded on 03/06/2011.

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c103-sp10-0412 - Chemistry 103 Spring 2010 Today 1...

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