PHYS102hw1 - HOMEWORK Ch 10 5,7,21,22,27,31,33,36,42,51...

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HOMEWORK Ch 10 5,7,21,22,27,31,33,36,42,51 10.5 Start with 40°F F T  and convert to Celsius.     55 32 40 32 40°C 99 CF TT   Since Celsius and Fahrenheit degrees of temperature change are different sizes, this is the only temperature with the same numeric value on both scales. 10.7 Apply 9 5 32 FC  to two different Celsius temperatures,     12 and CC , to obtain     1 1 9 32 5 [1] and     2 2 9 32 5 [2] Subtracting Equation [1] from [2] yields         21 9 5 F F C C T T T T   or   95 10.21 [Note that some rules concerning significant figures are deliberately violated in this solution to better illustrate the method of solution.] When the temperature of a material is raised, the linear dimensions of any cavity in that material expands as if it were filled with the surrounding material. Thus, the final value of the inner diameter of the ring will be given by   00 L L L T as       1 5 inner 2.168 cm 1.42 10 °C 2.168 cm 100°C 15.0°C 2.17 1 cm D 
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10.22 [Note that some rules concerning significant figures are deliberately violated in this solution to better illustrate the method of solution.]
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This note was uploaded on 03/07/2011 for the course PHYS 102 taught by Professor Armenn.kocharian during the Winter '11 term at California State University Los Angeles .

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PHYS102hw1 - HOMEWORK Ch 10 5,7,21,22,27,31,33,36,42,51...

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