{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Day34-1432class

# Day34-1432class - Math 1432 Dont forget online quizzes...

This preview shows pages 1–7. Sign up to view the full content.

Math 1432 Don’t forget online quizzes. THINK: Find the number to replace the question mark. 369542 is to 246359 as 172896 is to 268179 as 417638 is to ?

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Review: Geometric Series Test. The geometric series diverges if r 1 . If < r 1 , then the series converges to the sum = - 1 a S 1 r . The sum of the first n terms of a geometric series is ( 29 - = - n 1 a 1 r S 1 r . Ex. ( 29 = n n 1 3 1 2 .
Basic Divergence Test If → ∞ n n a 0 lim , then the series = n n 1 a diverges. Ex. = - + 2 2 n 1 n 1 n n

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
p-Series Test: A series of the form = = + + + + + p p p p p n 1 1 1 1 1 1 n 1 2 3 n ... ... The p-series diverges if < 0 p 1. The p-series converges if p > 1. Ex. = 8 n 1 27 n = 2 n 1 3 1 n
Integral Test : If f is positive , continuous , and decreasing for x 1 and ( 29 = n a n f , then = n n 1 a and ( 29 1 x dx f either both converge or both diverge. Ex. ( 29 = n 2 1 n n ln

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Basic Comparison Test: If n a 0 and n b 0 and 1) If = n n 1 b converges and n n 0 a b , then = n n 1 a converges.
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern