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Unformatted text preview: Chapter 31 Properties of Light 26 • Calculate the fraction of light energy reflected from an air–water interface at normal incidence. Picture the Problem Use the equation relating the intensity of reflected light at normal incidence to the intensity of the incident light and the indices of refraction of the media on either side of the interface. Express the intensity I of the light reflected from an airwater interface at normal incidence in terms of the indices of refraction and the intensity I of the incident light: 2 water air water air I n n n n I + = Solve for the ratio I / I : 2 water air water air + = n n n n I I Substitute numerical values and evaluate I / I : % . 2 33 . 1 00 . 1 33 . 1 00 . 1 2 = + = I I 31 •• [SSM] A slab of glass that has an index of refraction of 1.50 is submerged in water that has an index of refraction of 1.33. Light in the water is incident on the glass. Find the angle of refraction if the angle of incidence is ( a ) 60º, ( b ) 45º, and ( c ) 30º. Picture the Problem Let the subscript 1 refer to the water and the subscript 2 to the glass and apply Snell’s law to the waterglass interface. Apply Snell’s law to the water glass interface to obtain: 2 2 1 1 sin sin θ θ n n = Solving for θ 2 yields: = 1 2 1 1 2 sin sin θ θ n n ( a ) Evaluate θ 2 for θ 1 = 60 ° : ° = ° = 50 60 sin 50 . 1 33 . 1 sin 1 2 θ ( b ) Evaluate θ 2 for θ 1 = 45 ° : ° = ° = 39 45 sin 50 . 1 33 . 1 sin 1 2 θ ( c ) Evaluate θ 2 for θ 1 = 30 ° : ° =...
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This note was uploaded on 03/07/2011 for the course PHY 303L taught by Professor Turner during the Spring '08 term at University of Texas.
 Spring '08
 Turner
 Physics, Energy, Light

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