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Unformatted text preview: the speakers, in which case the centertocenter separation is d = [speaker separation]+[speaker width] = 3.5 m + 0.44 m = 3.94 m, and the corresponding angles are 0, 15.8, 33.0, and 54.7. Either case received full marks. Q2B.12 When light of wavelength is diffracted by a single slit of width 'a', the nulls in the diffraction pattern occur at angles n (measured from the central maximum) given by (These n clearly have a different meaning than the n in the previous problem!) If the angle between the first two nulls on either side of the central maximum is 1.2, then each null makes an angle of 0.6 with respect to the central maximum. Therefore, 1 = 0.6, and if = 633 nm = 0.633 m we calculate the slit width to be a = 60.4 m. n = sin1 n d n = sin 1 n a , and 1 = sin 1 a for the first null....
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This note was uploaded on 03/07/2011 for the course PHYS 274 taught by Professor Ericszarmes during the Spring '11 term at University of Hawaii, Manoa.
 Spring '11
 EricSzarmes
 Physics

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