Daily_017.SOLN - Q8B.3 For the diatomic CO molecule, the...

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Phys 274 – c ± Eric B. Szarmes 2 March 2011 Daily Homework 17 SOLUTIONS Q8B.2 The longest wavelength emitted by an electron in a box corresponds to the 2 1 transition ( n init = 2; n final = 1), which has the smallest energy spacing and hence the longest wavelength. Using eq. Q8.5b with L = 0 . 32 nm, we calculate λ = hc E ph = 8 mc 2 L 2 hc ( n 2 init - n 2 final ) = 8 (511 , 000 eV) (0 . 32 nm) 2 (1240 eV · nm) (2 2 - 1 2 ) = 113 nm , (1) which is shorter than visible.
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Unformatted text preview: Q8B.3 For the diatomic CO molecule, the value of ~ is measured to be 0.269 eV. Refering to the rst equality in eq. Q8.6, we calculate the wavelength of the photon emitted by the 3 2 vibrational transition to be = hc ~ ( n init-n nal ) = (1240 eV nm) (0 . 269 eV) (3-2) = 4 , 610 nm = 4 . 61 m . (2) 1...
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This note was uploaded on 03/07/2011 for the course PHYS 274 taught by Professor Ericszarmes during the Spring '11 term at University of Hawaii, Manoa.

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