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View Full DocumentQ# Question Text 5) Part I Analysis. Scoring Scheme: 3-2-1-1 Given the Nernst equation, E cell = (E cathode- E anode ) - [0.0257/n]lnQ, and the equation, E cell = E cathode- E anode , substitute E cell into the Nernst equation and solve for E cell . Which of the following would be the correct expression for E cell ? Your Answer: c. E cell = E cell + [0.0257/n]lnQ You Scored 3 points out of 3 Possible 6) Part I Analysis. Scoring Scheme: 3-2-1-1 For the cell, Zn(s) | Zn(NO 3 ) 2 (0.10M) || Cu(NO 3 ) 2 (0.10M) | Cu(s), which of the following is the correct spontaneous overall cell reaction: Your Answer: a. Zn(s) + Cu 2+ (aq) -> Zn 2+ (aq) + Cu(s) You Scored 3 points out of 3 Possible 7) Part I Analysis. Data Entry - No Scoring Please enter the value of E cell you measured in volts for the spontaneous cell reaction for Zn(s) | Zn(NO 3 ) 2 (0.10M) || Cu(NO 3 ) 2 (0.10M) | Cu(s). E cell = Your Answer: 0.7940 No Points Possible 8) Part I Analysis. Scoring Scheme: 3-2-1-1 For the cell, Zn(s) | Zn(NO 3 ) 2 (0.10M) || Cu(NO 3 ) 2 (0.10M) | Cu(s), which of the following is the correct expression for Q, the reaction quotient in the Nernst equation, for the spontaneous overall cell reaction: Your Answer: a. Q = [Zn 2+ ]/[Cu 2+ ] You Scored 3 points out of 3 Possible 9) Part I Analysis. Scoring Scheme: 3-3-2-1 Using your cell concentrations and the reaction quotient expression, calculate and enter the value of Q for the Nernst equation for this cell, Zn(s) | Zn(NO 3 ) 2 (0.10M) || Cu(NO 3 ) 2 (0.10M) | Cu(s) Q = Your Answer: 1 You Scored 3 points out of 3 Possible 10 ) Part I analysis. Scoring Scheme: 3-3-2-1 Please enter the value of lnQ that appears in the Nernst equation for this cell, Zn(s) | Zn(NO 3 ) 2 (0.10M) || Cu(NO 3 ) 2 (0.10M) | Cu(s) . ln Q = Your Answer: You Scored 3 points out of 3 Possible 11 ) Part I analysis. Scoring Scheme: 3-3-2-1 For the cell, Zn(s) | Zn(NO 3 ) 2 (0.10M) || Cu(NO 3 ) 2 (0.10M) | Cu(s), put all the terms together that enter into the equation for E cell , and enter the value you calculated for it. E cell = Your Answer: 0.7940 You Scored 3 points out of 3 Possible 12 ) Part I analysis. Data Entry - No Scoring Please enter the accepted value from the table in your text for the standard electrode potential, E , for the half-cell reaction for copper: Cu 2+ (aq) + 2e--> Cu(s) in volts. You will use this value as a reference to calculate the standard electrode potentials for the other half- reactions involved in the cells you measured. E (Cu 2+ /Cu) = Your Answer: 0.34 No Points Possible 13 ) Part I analysis. Scoring Scheme: 3-3-2-1 Using the equation E cell = E cathode- E anode , and the reference value of E for Cu(II)/Cu(s) for the role that copper plays in this overall cell reaction, determine the value of the standard potential for the half-reaction Zn 2+ (aq) + 2e--> Zn(s) and enter it here. ... View Full Document
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