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Q#
Question Text
5) Part I Analysis.
Scoring Scheme: 3211
Given the Nernst equation, E
cell
= (E
0
cathode
 E
0
anode
)  [0.0257/n]lnQ, and the equation, E
0
cell
= E
0
cathode

E
0
anode
, substitute E
0
cell
into the Nernst equation and solve for E
0
cell
.
Which of the following would be the correct expression for E
0
cell
?
Your Answer:
c. E
0
cell
= E
cell
+ [0.0257/n]lnQ
You Scored
3
points out of
3
Possible
6) Part I Analysis.
Scoring Scheme: 3211
For the cell, Zn(s)  Zn(NO
3
)
2
(0.10M)  Cu(NO
3
)
2
(0.10M)  Cu(s), which of the following is the correct
spontaneous overall cell reaction:
Your Answer:
a. Zn(s) + Cu
2+
(aq) > Zn
2+
(aq) + Cu(s)
You Scored
3
points out of
3
Possible
7) Part I Analysis.
Data Entry  No Scoring
Please enter the value of E
cell
you measured in volts for the spontaneous cell reaction for
Zn(s)  Zn(NO
3
)
2
(0.10M)  Cu(NO
3
)
2
(0.10M)  Cu(s).
E
cell
=
Your Answer:
0.7940
No Points Possible
8) Part I Analysis.
Scoring Scheme: 3211
For the cell, Zn(s)  Zn(NO
3
)
2
(0.10M)  Cu(NO
3
)
2
(0.10M)  Cu(s),
which of the following is the correct expression for Q, the reaction quotient in the Nernst equation, for the
spontaneous overall cell reaction:
Your Answer:
a. Q = [Zn
2+
]/[Cu
2+
]
You Scored
3
points out of
3
Possible
9) Part I Analysis.
Scoring Scheme: 3321
Using your cell concentrations and the reaction quotient expression, calculate and enter the value of Q for
the Nernst equation for this cell,
Zn(s)  Zn(NO
3
)
2
(0.10M)  Cu(NO
3
)
2
(0.10M)  Cu(s)
Q =
Your Answer:
1
You Scored
3
points out of
3
Possible
10
)
Part I analysis.
Scoring Scheme: 3321
Please enter the value of lnQ that appears in the Nernst equation for this cell,
Zn(s)  Zn(NO
3
)
2
(0.10M)  Cu(NO
3
)
2
(0.10M)  Cu(s) .
ln Q =
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View Full DocumentYour Answer:
0
You Scored
3
points out of
3
Possible
11
)
Part I analysis.
Scoring Scheme: 3321
For the cell, Zn(s)  Zn(NO
3
)
2
(0.10M)  Cu(NO
3
)
2
(0.10M)  Cu(s),
put all the terms together that enter into the equation for E
0
cell
, and enter the value you calculated for it.
E
0
cell
=
Your Answer:
0.7940
You Scored
3
points out of
3
Possible
12
)
Part I analysis.
Data Entry  No Scoring
Please enter the accepted value from the table in your text for the standard electrode potential, E
0
, for the
halfcell reaction for copper:
Cu
2+
(aq) + 2e

> Cu(s) in volts.
You will use this value as a reference to calculate the standard electrode potentials for the other half
reactions involved in the cells you measured.
E
0
(Cu
2+
/Cu) =
Your Answer:
0.34
No Points Possible
13
)
Part I analysis.
Scoring Scheme: 3321
Using the equation E
0
cell
= E
0
cathode
 E
0
anode
, and the reference value of E
0
for Cu(II)/Cu(s) for the role that
copper plays in this overall cell reaction, determine the value of the standard potential for the halfreaction
Zn
2+
(aq) + 2e

> Zn(s) and enter it here.
Standard potential =
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 Summer '08
 Enderle
 Chemistry

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