Chem%20161-2007%20exam%20II%20%2B%20answers

Chem%20161-2007%20exam%20II%20%2B%20answers - Chemistry 161...

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Chemistry 161 Exam II October 24, 2007 Student Name (Print): _____TAVSS _______________ Section Number: FF RUID: FFFFFFFFF Recitation Instructor: __________________ The exam booklet has 25 questions for credit and one additional question to check the color of your exam booklet. Please answer all 26 questions on the OpScan sheet. There is no penalty for guessing. At the end of the 80-minute exam period, please hand in only this top sheet and your OpScan form. If you finish early, please do not disturb your fellow students. A proctor will check your picture ID, OpScan form, signature and calculator during the exam. The use of calculators with permanent memories (graphing calculators), cell phones, pagers, PDAs or other electronic devices other than a basic scientific calculator is expressly forbidden. The last page of the booklet contains a periodic table along with other useful data. The use of any other notes or information on this test will be considered a violation of the Academic Honesty provisions of the student code. Exam scores will be posted as soon as possible. There is a five point penalty for failing to bubble in your information! ON THE OpScan FORM (Use a #2 pencil or darker) Sec Per. Instr Sec Per. Instr 1. SIGN your name across the top of the form. 01 M3 EC 19 M1 HS 2. Code the following information ( blacken circles) 02 M5 EC 20 M3 HH Your Name (LAST NAME FIRST) 03 M5 GG 21 M3 GG Your RU ID NUMBER 04 W3 DS 22 W1 HS [Start under Box A and continue to Box I ] 05 W5 RA 23 W1 ET Your RECITATION SECTION NUMBER in 06 W5 KN 24 W3 GG [Sections 01-09, code a 0 under box K ] 07 F3 KN 25 Th1 ET Your EXAM FORM NUMBER under box P 08 F5 KN 26 Th1 SM 09 F5 LP 27 Th3 LP AM = A. McGhan, DS = D. Siegel, EC = E. Ciftlikli 28 Th3 SM ET = E. Tavss, GG = G. Govindarajoo, HS = H. Sangari OS AM Please bubble 99 29 Th3 ET HH = H. Haubenstock, KN = K. Norton, 12 M2 HS 30 M6 BL BL = B. Langowski, LP = L. Petrone, 13 W2 HS 31 M6 RP SM = S. Marvasti, RP = R. Porcja, RA = R. Agarwal 14 W2 HH 32 M6 EC Periods: 1 = 9:30-10:25, 2 = 11:10-12:05 15 Th2 LP 33 W6 RP 3 = 12:15-1:10 or 12:50-1:45 16 M2 SM 34 W6 RA 5 = 3:35-4:30, 6 = 5:15-6:10, 8 = 8:25p-9:20p 17 W2 RA 35 M8 BL Your EXAM FORM is c 18 M1 SM 36 M8 RP C161f07e2v1 1
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c 1 Chem 161-2007 Exam II Hill, Petrucci et al., 4 th edition Chapter 3B - Stoichiometry Reaction stoichiometry 4MnO 4 - (aq) + 3ClO 2 - (aq) + 2H 2 O( l ) 4MnO 2 (s) + 3ClO 4 - (aq) + 4OH - (aq) According to the balanced equation above, how many moles of ClO 2 - (aq) are needed to react completely with 20.0 mL of 0.20 M KMnO 4 solution? A. 0.0060 mol B. 0.0053 mol C. 0.0075 mol D. 0.013 mol E . 0.0030 mol 4MnO 4 - (aq) + 3ClO 2 - (aq) + 2H 2 O( l ) 4MnO 2 (s) + 3ClO 4 - (aq) + 4OH - (aq) 0.020L ?mol 0.20M mol = M x V 0.20M x 0.020 L = 0.004 mol KMnO 4 . According to the equation above, 3 mol ClO
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Chem%20161-2007%20exam%20II%20%2B%20answers - Chemistry 161...

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