s10q10 - 1. Chem 171 Quiz 10 Version A (Key Enthalpy CO2)...

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Chem 171 Quiz 10 Version A (Key Enthalpy CO 2 ) 1. The fuel value of a hamburger is approximately 3.6 kcal / g. If a person eats 1 pound of hamburger for lunch and if none of the energy is stored in his body, estimate the amount of water in kg that would have to be lost in perspiration to keep his body temperature constant. The heat of vaporization of water is 2.41 kJ / g. 1 pound = 453.6 g. 4.184 J / cal. q = specific heat capacity x mass x Δ T. Calculate the heat content (in kJ) of 1 lb of hamburger: (3.6 kcal/g)(4.184 kJ/kcal)(453.6 g/lb) = 6.83 × 10 3 kJ Then determine what mass of water could be vaporized by that amount of heat: mass of water = (6.83 × 10 3 kJ) kJ 2.41 g 1 = 2.8 × 10 3 g or 2.8 kg 2. The following questions refer to the experiment entitled “Determining the Molar Volume of Carbon Dioxide”. R = 0.0821 L atm / K mol. PV = nRT. What is the objective of this experiment. How do you achieve your objective. In this experiment, we will calculate the molar volume of CO 2 gas in L / mol by determining the mass of a known volume of CO 2 gas at laboratory temperature and pressure.
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This note was uploaded on 03/08/2011 for the course CHEM 171 taught by Professor Several during the Spring '08 term at Rutgers.

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s10q10 - 1. Chem 171 Quiz 10 Version A (Key Enthalpy CO2)...

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