Doncouse_Jeremy_Week6

Doncouse_Jeremy_Week6 - Jeremy Doncouse Student ID: 92575...

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Jeremy Doncouse Student ID: 92575 MATH116 For Excercises 6-25, find the area under the standard normal distribution curve. 6 Between z = 0 and z = 1.89 0 = 0.5 0.9706-0.5 = 0.4706 1.89 = 0.9706 8 Between z = 0 and z = -0.46 0.5 0.5 - 0.3228 = 0.1772 0.32 10 To the right of z = 2.11 1 - 0.9826 = 0.0714 12 To the left of z = -0.75 0.23 14 Between z = 1.23 and z = 1.90 0.9713 - 0.8907 = 0.0806 In Exercises 26-39, find the probabilities for each, using the standard normal distribution. 26 P(0 < z < 1.96) 0.9750 - 0.5 = 0.475 28 P(-1.23 < z < 0) 0.5 - 0.1093 = 0.3907 30 P(z > 0.82) 1 - 0.7939 = 0.2061 32 P(z < -1.77) 0.04 34 P(-0.20 < z < 1.56) 0.9406 - 0.4207 = 0.5199 40 Find the z value such that the area under the standard normal deviation curve between 0 and the z value is 0.4066. 0.5 + 0.4066 = 0.9066 0.9066 = 1.32 41 Find the z value such that the area under the standard normal deviation curve between the z value and 0 is 0.4175. 0.5 - 0.4175 = 0.0825 0.0825 ≈ -1.39 42 Find the z value such that the area under the standard normal deviation curve > z is 0.0239. 1 - 0.0239 = 0.9761 0.9761 = 1.98 43 Find the z value such that the area under the standard normal deviation curve < z is 0.0188. -2.08 44 P( < z = 0.9671) 1.84 45 P( > z = 0.8962) 1 - 0.8962 = 0.1038 = -1.26 46 Find the z value to the right of the mean so that Section 6.1: (Page 309) 6-25 (any five even numbered), 26-39 (any five even numbered), 40-47
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Doncouse_Jeremy_Week6 - Jeremy Doncouse Student ID: 92575...

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