Jeremy Doncouse
Student ID: 92575
MATH116
For Excercises 625, find the area under the standard normal distribution curve.
6
Between z = 0 and z = 1.89
0 = 0.5
0.97060.5 = 0.4706
1.89 = 0.9706
8
Between z = 0 and z = 0.46
0.5
0.5  0.3228 = 0.1772
0.32
10
To the right of z = 2.11
1  0.9826 = 0.0714
12
To the left of z = 0.75
0.23
14
Between z = 1.23 and z = 1.90
0.9713  0.8907 = 0.0806
In Exercises 2639, find the probabilities for each, using the standard normal distribution.
26
P(0 < z < 1.96)
0.9750  0.5 = 0.475
28
P(1.23 < z < 0)
0.5  0.1093 = 0.3907
30
P(z > 0.82)
1  0.7939 = 0.2061
32
P(z < 1.77)
0.04
34
P(0.20 < z < 1.56)
0.9406  0.4207 = 0.5199
40
Find the z value such that the area under the standard normal deviation curve between 0 and the z
value is 0.4066.
0.5 + 0.4066 = 0.9066
0.9066 = 1.32
41
Find the z value such that the area under the standard normal deviation curve between the z value
and 0 is 0.4175.
0.5  0.4175 = 0.0825
0.0825 ≈ 1.39
42
Find the z value such that the area under the standard normal deviation curve > z is 0.0239.
1  0.0239 = 0.9761
0.9761 = 1.98
43
Find the z value such that the area under the standard normal deviation curve < z is 0.0188.
2.08
44
P( < z = 0.9671)
1.84
45
P( > z = 0.8962)
1  0.8962 = 0.1038 = 1.26
46
Find the z value to the right of the mean so that
Section 6.1:
(Page 309) 625 (any five even numbered), 2639 (any five even numbered), 4047
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 Fall '09
 Unknown
 Math, Statistics, Normal Distribution, Standard Deviation, σ, standard normal deviation, normal deviation curve

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