{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

physics_6c_su08_exam_3

# physics_6c_su08_exam_3 - PHYSICS 6C Summer 2008 EXAM#3...

This preview shows pages 1–2. Sign up to view the full content.

PHYSICS 6C Summer 2008 EXAM #3 Elementary Charge Electrostatic force on charge: e = 1.602 x 10 -19 C F = q E Coulomb’s Law: Electrostatic field of a point charge: F = kQq/r 2 E = (kQ/r 2 ) (k = 8.99 x 10 9 N-m 2 /C 2 ) Direction of E is away from positive charge Field near a plane of charge on a conductor: Electron Volt: E = σ / ε 0 1 eV = 1.602 x 10 -19 J σ = surface charge density ε 0 = 8.85 x 10 -12 F/m Superposition Principle: If E 1 , E 2 , E 3 are electrostatic fields at a point caused Gauss’s Law by charges q 1 , q 2 , q 3 , the total field at that point is: 0 / ε Q = ∫∫ dA E E = E 1 + E 2 + E 3 (Vector addition!) Electrostatic Potential Difference: Potential of a Point Charge: Δ V = = -(Electrostatic Work)/q V = kQ/r dl E Electrostatic Potential Energy: Capacitors: EPE = qV Q = CV Electrostatic energy = (1/2)CV 2 Superposition Principle (Potentials) Parallel plate capacitor: C = κε 0 A/d If V 1 , V 2 , V 3 are electrostatic potentials Magnitude of field in dielectric, E = E 0/ κ at a point caused by charges q 1 , q 2 , q 3 , (E 0 is magnitude of field in vacuum)

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern