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Unformatted text preview: rathbun (rar2954) – Homework 3 – vanden bout – (51640) 1 This printout should have 41 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 10.0 points What is the main overall driving force for any spontaneous reaction or change? 1. To release heat energy. 2. To lower the available free energy. cor rect 3. To maximize entropy. 4. To obey the laws of gravity. 5. To maximize electrostatic interactions. Explanation: 002 10.0 points When the chemical reaction A + B C + D is at equilibrium, 1. neither the forward nor the reverse reac tions have stopped. correct 2. the forward reaction has stopped. 3. the sum of the concentrations of A and B equals the sum of the concentrations of C and D. 4. all four concentrations are equal. 5. the reverse reaction has stopped. 6. both the forward and reverse reactions have stopped. Explanation: Chemical equilibrium is dynamic equilib rium, with both foward and reverse processes occuring at the same rate. 003 10.0 points Equilibria involving species in more than one phase are called 1. homogeneous equilibria. 2. chemical equilibria. 3. reversible reaction. 4. heterogeneous equilibria. correct Explanation: If all components of the equilibrium system are in the same phase, equilibrium is homoge nous; if more than one phase is represented in the system, equilibrium is heterogenous. 004 10.0 points Write the equilibrium expression for the fol lowing reaction: 2 NO ( aq ) + 4 H 2 O( ) ←→ 3 H 2 ( aq ) + 2 H + ( aq ) + 2 NO 3 ( aq ) 1. K = [ H 2 ] 3 · [ H + ] 2 · [ NO 3 ] 2 [ NO ] 2 · [ H 2 O ] 4 2. K = [ NO ] 2 [ H + ] 2 · [ NO 3 ] 2 3. K = [ H 2 ] 3 · [ H + ] 2 · [ NO 3 ] 2 [ NO ] 2 correct 4. K = [[ H + ] 2 · [ NO 3 ] 2 [ NO ] 2 5. K = [ NO ] 2 [ H 2 ] 3 · [ H + ] 2 · [ NO 3 ] 2 Explanation: Set up K , products in the numerator, reac tants in the denominator, all raised to respec tive stoichiometric coefficients. 005 10.0 points The following equilibrium exists in a closed container: N 2 ( g ) + O 2 ( g ) ←→ 2 NO( g ) rathbun (rar2954) – Homework 3 – vanden bout – (51640) 2 If the partial pressures of N 2 , O 2 and NO at equilibrium are 1 . 5 atm, 2 . 5 atm and . 75 atm respectively, what is the equilbrium constants? 1. K = 0.15 correct 2. K = 5 3. K = 0.2 4. K = 6.67 Explanation: K = P 2 NO P N 2 · P O 2 = . 75 2 1 . 5 · 2 . 5 = 0 . 15 006 10.0 points K c = 4 . 9 × 10 5 for the reaction A(g) 2 B(g) . What is K c for the reaction 2 B(g) A(g) ? 1. 3 . 40 × 10 6 2. 2 . 04 × 10 6 correct 3. 9 . 81 × 10 6 4. 1 . 59 × 10 6 5. 2 . 45 × 10 6 Explanation: 007 10.0 points Given the following equilibria and equilibrium constants K 1 CO(g) + H 2 O(g) CO 2 (g) + H 2 (g) K 2 CH 4 (g) + H 2 O(g) CO(g) + 3 H 2 (g) K 3 CH 4 (g) + 2 H 2 O(g) CO 2 (g) + 4 H 2 (g) The correct expression for K 3 in terms of K 1 and K 2 is 1. Cannot be determined from this informa tion....
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This note was uploaded on 03/08/2011 for the course CHEM 302 taught by Professor Mccord during the Spring '10 term at University of Texas.
 Spring '10
 McCord
 Chemistry

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